I'm wondering if something like this is possible. Let's suppose this snippet of code:
area = ["A","B","C"] level = ["L1","L2","L3"] sector = [area, level] print(sector) print(sector[1]) Output:
[['A', 'B', 'C'], ['L1', 'L2', 'L3']]['L1', 'L2', 'L3']The first print is OK for me. It shows the lists and their elements.
However, for the second print I would like to have the name of the list instead of its elements. In this case level
Is that possible?
What you can do though, is use a dictionnary:
di = {"area": ["A", "B", "C"], "level": ["L1", "L2", "L3"]} di["area"] Output :
["A", "B", "C"] 
You could compare the id:
for sec in sector: if id(sec) == id(area): print('area') elif id(sec) == id(level): print('level') etc.
However, this is a dubious way to go. Why do you need this?
Make it into a Dictionary of Lists instead of a List of Lists:
area = ["A","B","C"] level = ["L1","L2","L3"] sectors = { "area": area, "level": level } print(sectors["level"]) print(sectors["area"]) """ some other useful dict methods below """ print(sectors.keys()) print(sectors.values()) print(sectors.items()) You can use a dictionary for your usecase.
You can make the name of the variables as key and lists as values.
Try this:
area = ["A","B","C"] level = ["L1","L2","L3"] sector = {"area":area, "level":level} print(list(sector.values())) print(list(sector.keys())) Outputs:
[['A', 'B', 'C'], ['L1', 'L2', 'L3']] ['area', 'level'] 