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I can't seem to get this right. I have a matrix A, and it's upper off-diagonal elements in column order

A [,1] [,2] [,3] [,4] [1,] 1 5 9 13 [2,] 2 6 10 14 [3,] 3 7 11 15 [4,] 4 8 12 16 A[col(A) > row(A)] [1] 5 9 10 13 14 15

How would I get these elements in row order? In this case: 5 9 13 10 14 15

Thank you

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    t(A)[lower.tri(A)] Commented Dec 7, 2021 at 22:52
  • B <- t(A); B[col(B) < row(B)] seems to work. Commented Dec 7, 2021 at 22:53

1 Answer 1

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m <- matrix(1:25, 5, 5) [,1] [,2] [,3] [,4] [,5] [1,] 1 6 11 16 21 [2,] 2 7 12 17 22 [3,] 3 8 13 18 23 [4,] 4 9 14 19 24 [5,] 5 10 15 20 25 t(m)[lower.tri(m)] [1] 6 11 16 21 12 17 22 18 23 24
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