Java: How to call super method from inner in-place class

Question

I have base class Foo with method spam and class Bar which overrides spam. I need to call spam of base class in method of some callback object which is defined in-place:

public class Foo { public void spam() { // ... } } public class Bar extends Foo { @Override public void spam() { objectWhichRequireCallback(new Callback { @Override public void onCallback() { super.spam(); } }); } }

This code is not working because super is related to Callback, not Bar class. Is it possible to call super method from object defined in-place?

Have you tried this.Foo.super.span()?

SJuan76
– SJuan76

2011-08-16 14:18:00 +00:00
Commented Aug 16, 2011 at 14:18 — SJuan76
– SJuan76, Commented Aug 16, 2011 at 14:18

Kal · Accepted Answer · 2011-08-16 14:24:44Z

34

public class Bar extends Foo { @Override public void spam() { objectWhichRequireCallback(new Callback { @Override public void onCallback() { Bar.super.spam(); } }); } }

EDIT : Sorry. DIdn't realize the method names are the same.

edited Aug 16, 2011 at 14:24

answered Aug 16, 2011 at 14:18

Kal

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2 Comments

Alistair A. Israel Over a year ago

StackOverflow ;-)

Vlad Over a year ago

I was sure that I tried this approach before asking question, but Eclipse gave me error. It seems that I was inattentive. Now I retried. It works! Thanks!

AlexR · Accepted Answer · 2011-08-16 14:23:55Z

4

Try this: Bar.super.spam();

Bar.this.spam(); is compiled but it will cause infinite recursion because you call the same spam() itself.

answered Aug 16, 2011 at 14:23

AlexR

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1 Comment

Sam DeHaan Over a year ago

Everybody loves a good Stack Overflow. I mean, we're here, after all.

Sam DeHaan · Accepted Answer · 2011-08-16 14:18:40Z

3

You can create a wrapper function for this, in Bar

public class Bar... public void mySuperSpam(){ super.spam(); }

answered Aug 16, 2011 at 14:18

Sam DeHaan

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1 Comment

Hovercraft Full Of Eels Over a year ago

Shouldn't that be mySuperDuperSpam? :)

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