python - convert datetime to UTC time

Question

I would like to convert datetime to UTC time. I try below code but the output looks like not correct:

import datetime import pandas as pd def str2dt(tstr): dt = datetime.datetime.strptime(tstr, '%m-%d %H:%M:%S.%f') return dt ts = "04-12 20:43:34.342" dt = str2dt(ts) utc_delta = datetime.datetime.utcnow() - datetime.datetime.now() utc = dt - utc_delta print(dt,'->',utc)

Current output: 1900-04-12 20:43:34.342000 -> 1900-04-12 15:43:34.342001

The expected output time is 1900-04-12 02:43:34.342001

I think the use of the pytz for timezone is what you need to convert between local vs UTC — astrochun
– astrochun, Commented Apr 17, 2022 at 3:20

triskofwhaleisland · Accepted Answer · 2022-04-17 02:59:21Z

It looks like you would be better off using isoformat() on your datetime:

utc = dt.isoformat(sep=' ') # The normal date-time separator is 'T', but that isn't very readable print(f"{dt} -> {utc}")

This gives you the answer you're looking for.

If you still need the UTC offset, consider using datetime.datetime.utcoffset().

Not sure why it output the same time: 2022-04-12 20:43:34.342000 -> 2022-04-12 20:43:34.342000
Make sure that the timezone is being initialized accurately. Python might believe that the time is already at UTC+0.

user6018651 · Accepted Answer · 2022-04-17 02:34:38Z

Should be plus the delta:

import datetime import pandas as pd def str2dt(tstr): dt = datetime.datetime.strptime(tstr, '%m-%d %H:%M:%S.%f') return dt ts = "04-12 20:43:34.342" dt = str2dt(ts) utc_delta = datetime.datetime.utcnow() - datetime.datetime.now() utc = dt + utc_delta print(dt,'->',utc)

Output:

1900-04-12 20:43:34.342000 -> 1900-04-13 01:43:34.341999

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