Why does my code jump straight to default? Switch case in Go

Question

I am just starting Go and tried implementing switch statement. As far as I know this statement in other languages require "break;" but not in Go. Somehow my code jumps directly into default block. By the time I am writing this question, it is 23/04/2022, Saturday.

P.S. I would be grateful if any of you could suggest me any platforms, where I can take Go courses for free.

This is my code:

package main import ( "fmt" "time" ) func main() { fmt.Println("when is Sunday?") today := time.Now().Weekday() switch time.Sunday { case today + 0: fmt.Println("Today.") case today + 1: fmt.Println("Tommorow.") case today + 2: fmt.Println("In 2 days.") default: fmt.Println("Too far away.") } }

Dylan Reimerink · Accepted Answer · 2022-04-23 13:47:46Z

time.Sunday is a const with the value 0. In your switch you add 1 or 2 to today but the value doesn't loop back around to zero after it reaches a value of 6 (Satureday).

So the second and third clause of your switch will never be true.

This does what you want:

package main import ( "fmt" "time" ) func main() { fmt.Println("when is Sunday?") today := time.Now().Weekday() switch today { case time.Sunday: fmt.Println("Today.") case time.Saturday: fmt.Println("Tommorow.") case time.Friday: fmt.Println("In 2 days.") default: fmt.Println("Too far away.") } }

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