VS Code launch.json into an actual command

Question

I want to make a Python script that transforms a part of VS Code launch.json into a normal command for a terminal. I need it to communicate with non-VSCode users. Here is the example:

import json launch_json = ''' { "name": "temp", "type": "python", "request": "launch", "program": "script.py", "console": "integratedTerminal", "justMyCode": false, "args": ["abcd", "--log", "log.txt"], "env": {"CUDA_VISIBLE_DEVICES":"0"}, } ''' d = json.loads(launch_json) command = d["program"] + " " + " ".join(d["args"]) print(command)

If I run it, I have the following error:

json.decoder.JSONDecodeError: Expecting property name enclosed in double quotes: line 12 column 9 (char 344)

How do I make the script?

Remove the trailing comma on the last property value (env)

Sayse
– Sayse

2022-08-04 10:52:32 +00:00
Commented Aug 4, 2022 at 10:52 — Sayse
– Sayse, Commented Aug 4, 2022 at 10:52

Nawaf · Accepted Answer · 2022-08-04 10:55:21Z

There is an extra comma at the end of launch_json

{ "env": {"CUDA_VISIBLE_DEVICES":"0"}, <- should not be here }

so just replace it with

{ "name": "temp", "type": "python", "request": "launch", "program": "script.py", "console": "integratedTerminal", "justMyCode": false, "args": ["abcd", "--log", "log.txt"], "env": {"CUDA_VISIBLE_DEVICES":"0"} }

Collectives™ on Stack Overflow

VS Code launch.json into an actual command

1 Answer 1

Comments

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Related