About jQuery.Deferred()

Question

I'm studying some use-case in Deferred, and I came by this instruction:

$.Deferred().reject().promise()

I don't get it, under what condition we call reject() then directly we call promise()?

I mean, if we want to reject the deferred object, how can the rejected deferred represent a promise?

Matt · Accepted Answer · 2011-09-16 15:31:30Z

3

When we call .reject() and then .promise(), we are returning a promise that we have already decided will not succeed. Any handlers bound with .fail() or .always() will be immediately invoked upon them being added.

answered Sep 16, 2011 at 15:31

Matt

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Ken D Over a year ago

Does this mean that if we want any handlers bound with .done() to be invoked immediately, we call $.Deferred.resolve().prmoise()?

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