I have a sentence
s = 'john had a little blue car' which I want to split into three different strings (of word length 2) to obtain
'john had' 'a little' 'blue car' How can I do this using split? First I tried splitting via
s.split(" ") to give
['john', 'had', 'a', 'little', 'blue', 'car'] how can I now take that list of words and join them to obtain the result I want?
Using a regex:
import re r = r"(\w+\s+\w+)" s = "john had a little blue car" m = re.findall(r, s) (\w+\s+\w+)
Regex101 Demo
\w: matches any word character\s: matches any whitespace+ : as many times possibleReturn all non-overlapping matches of pattern in string, as a list of strings or tuples.
A native Python way is to use the s.split() as you described, and then 'splice' the array and join() them back together in groups of 2 using a for loop with range(0, len(s), 2) to take steps of 2:
s = 'john had a little blue car' s = s.split(" ") s = [' '.join(s[i : i + 2]) for i in range(0, len(s), 2)] Both result in:
['john had', 'a little', 'blue car'] Not the fastest way to be honest:
s = 'john had a little blue car'.split() for i in range(0, len(s), 2): print(f"{s[i]} {s[i+1]}") Where: s[i] - first elem of pair, s[i+1] - second elem of a pair
The result you wants is a bit blurry, but here a few ways
Using for loop to iterate over the string and combining pairs of words together:
s = 'john had a little blue car' words = s.split() for i in range(0, len(words), 2): w1 = words[i] w2 = words[i+1] print(w1, w2) if you want to save the result than :
s = 'john had a little blue car' split_list = [] words = s.split() for i in range(0, len(words), 2): w1 = words[i] w2 = words[i+1] split_list.append([w1, w2]) after the code you will have in split_list in each cell the 2 of the words
Using the zip function to iterate over the string and combining pairs of words together (Might not familiar with Zip but its a very helpful tool):
s = 'john had a little blue car' words = s.split() for w1, w2 in zip(words[::2], words[1::2]): print(w1, w2) if you want to save the result than :
s = 'john had a little blue car' split_list = [] words = s.split() for w1, w2 in zip(words[::2], words[1::2]): split_list.append([w1, w2]) after the code you will have in split_list in each cell the 2 of the words
s = 'john had a little blue car'.split(' ') #['john', 'had', 'a', 'little', 'blue', 'car'] s[0::2] #['john', 'a', 'blue'] s[1::2] #['had', 'little', 'car'] list(zip(s[0::2],s[1::2])) #[('john', 'had'), ('a', 'little'), ('blue', 'car')] Or for desired output:
[' '.join(x) for x in zip(s[0::2],s[1::2])] #['john had', 'a little', 'blue car'] Here is a one-liner that will get the results you want.
s = 'john had a little blue car' print '\n'.join(' '.join([s.split()[i].strip(), s.split()[i+1] if i < len(s.split()) - 1 else '']) for i in range(0, len(s.split()), 2)) Output:
john had a little blue car Edit: Modified slightly to prevent errors when there are an odd number of words.
