Removing code repetition using casting operators [duplicate]

Question

class nums {  public: int sum(int a,int b) const {   return a+b; } int sum(int a,int b) {   return a+b; } }; int main() { const nums a; a.sum(5,10); nums  b; b.sum(1,2); }

I am trying remove two functions for const objects and non const objects replace with one function using casting operators.

With what you have right now, there's no reason for a non-const version, or even a non-static version — Ranoiaetep
– Ranoiaetep, Commented Feb 14, 2023 at 5:36
@Ranoiaetep the idea behind this is to explore how casting operators are useful and im trying to explore that. — iso42
– iso42, Commented Feb 14, 2023 at 6:08

justANewb stands with Ukraine · Accepted Answer · 2023-02-14 05:41:27Z

0

You can use int sum(int a,int b) const even if the object isn't marked as const. See this answer.

So, the following code would compile:

class nums { public: int sum(int a,int b) const { return a+b; } }; int main() { const nums a; a.sum(5,10); nums b; b.sum(1,2); }

Link to Compiler Explorer.

answered Feb 14, 2023 at 5:41

justANewb stands with Ukraine

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3 Comments

iso42 Over a year ago

Yes, that is possible but I want to explore how casting operators will work. Can we do this casting operators?

justANewb stands with Ukraine Over a year ago

@iso42 wdym by "casting operators" ?

iso42 Over a year ago

you can this refer to this link

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