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Stupid example:

some_function() { echo "here" } do_something () { local frame=0 local values=() while values=($(caller $frame)); do local fline=${values[0]} local fname=${values[1]} local fsource=${values[2]} echo "Line ${fline} of '${fname}' in file ${fsource}." ((frame++)) done echo "LINENO: $LINENO" echo "BASH_LINENO: ${BASH_LINENO[*]}" echo "FUNCNAME: ${FUNCNAME[*]}" echo "BASH_SOURCE: ${BASH_SOURCE[*]}" some_function } do_more () { # comment to change line numbering do_something } do_most () { do_more }

If I call "do_most", I get output such as

Line 3 of 'do_more' in file test_lineno.sh. Line 2 of 'do_most' in file test_lineno.sh. LINENO: 12 BASH_LINENO: 3 2 200 FUNCNAME: do_something do_more do_most BASH_SOURCE: test_lineno.sh test_lineno.sh test_lineno.sh here

But what I want are the line numbers in the file, e.g., line 28 for 'do_more' or line 33 for 'do_most'. Is there a way to get that from bash?

Bash version: GNU bash, version 5.2.15(1)-release (aarch64-apple-darwin21.6.0)

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    You might have a look at wiki.bash-hackers.org/scripting/…. See stackoverflow.com/questions/17804007/… Commented Feb 15, 2023 at 19:10
  • That could help in a particular instance, but I'm looking for a more general answer that could be scripted. I know about set -x, but it is not something I'd normally want turned on. Commented Feb 15, 2023 at 19:19
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    If I run your script appending do_most at the last line, I get the correct (absolute) line numbers. My bash version is "5.0.17(1)-release". Commented Feb 15, 2023 at 19:36
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    Aha! That's it. Apparently bash reports differently if I just source it vs. running it as a script. Probably points to more things about Bash I need to understand, but thank you! Might not help in my particular case (I'm sourcing a file in another script), but still some kind of progress. Commented Feb 15, 2023 at 19:42
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