How to retrieve dirs in a zipfile using python?

Question

How do I traverse the contents of a zip file in python without having to extract them?

If extracting is the only way, is it efficient if I create a unique temp folder and extract them there then traverse and remove the temp folder afterwards?

Are you using the zipfile module?

Greg Hewgill
– Greg Hewgill

2011-09-29 21:42:37 +00:00
Commented Sep 29, 2011 at 21:42 — Greg Hewgill
– Greg Hewgill, Commented Sep 29, 2011 at 21:42
@GregHewgill: Yes, I am.

Marconi
– Marconi

2011-09-30 00:33:34 +00:00
Commented Sep 30, 2011 at 0:33 — Marconi
– Marconi, Commented Sep 30, 2011 at 0:33

Adam Rosenfield · Accepted Answer · 2011-09-29 21:43:44Z

3

Use the namelist() method of the ZipFile class to get a list of all of the filenames in the archive without having to extract them. For example:

import zipfile myzip = zipfile.ZipFile('myzip.zip', 'r') filenames = myzip.namelist() # Do something with filenames

answered Sep 29, 2011 at 21:43

Adam Rosenfield

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7 Comments

Gabe Over a year ago

If the OP is trying to retrieve directories, he'll have to use infolist instead of namelist.

Marconi Over a year ago

@Gabe: In an ZipInfo object, I can't seem to find a suitable property or method which would tell me if the item was a dir or not.

Marconi Over a year ago

@Adam: Lets say I have the filenames, those are just strings. How can I tell which are directories and files?

Greg Hewgill Over a year ago

@Marconi: Often zip file won't have entries for individual directories at all. But if they do, check for a trailing /.

Marconi Over a year ago

@GregHewgill: Yeah, it looks like its impossible to fully traverse the archive without extracting it first.

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