272

Given an absolute or relative path (in a Unix-like system), I would like to determine the full path of the target after resolving any intermediate symlinks. Bonus points for also resolving ~username notation at the same time.

If the target is a directory, it might be possible to chdir() into the directory and then call getcwd(), but I really want to do this from a shell script rather than writing a C helper. Unfortunately, shells have a tendency to try to hide the existence of symlinks from the user (this is bash on OS X):

$ ls -ld foo bar drwxr-xr-x 2 greg greg 68 Aug 11 22:36 bar lrwxr-xr-x 1 greg greg 3 Aug 11 22:36 foo -> bar $ cd foo $ pwd /Users/greg/tmp/foo $ 

What I want is a function resolve() such that when executed from the tmp directory in the above example, resolve("foo") == "/Users/greg/tmp/bar".

0

21 Answers 21

486
readlink -f "$path" 

Editor's note: The above works with GNU readlink and FreeBSD/PC-BSD/OpenBSD readlink, but not on OS X as of 10.11.
GNU readlink offers additional, related options, such as -m for resolving a symlink whether or not the ultimate target exists.

Note since GNU coreutils 8.15 (2012-01-06), there is a realpath program available that is less obtuse and more flexible than the above. It's also compatible with the FreeBSD util of the same name. It also includes functionality to generate a relative path between two files.

realpath $path 

[Admin addition below from comment by halloleodanorton]

For Mac OS X (through at least 10.11.x), use readlink without the -f option:

readlink $path 

Editor's note: This will not resolve symlinks recursively and thus won't report the ultimate target; e.g., given symlink a that points to b, which in turn points to c, this will only report b (and won't ensure that it is output as an absolute path).
Use the following perl command on OS X to fill the gap of the missing readlink -f functionality:
perl -MCwd -le 'print Cwd::abs_path(shift)' "$path"

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16 Comments

This doesn't work in Mac OS X - see stackoverflow.com/questions/1055671/…
On OS X you can install coreutils with homebrew. It installs it as "grealpath".
readlink works on OSX, but needs another syntax: readlink $path without the -f.
readlink fails to de-reference multiple layers of symlink though, it just derefs one layer at a time
No solaris doesn't have these. You would need to build GNU coreutils for your system.
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106

According to the standards, pwd -P should return the path with symlinks resolved.

C function char *getcwd(char *buf, size_t size) from unistd.h should have the same behaviour.

getcwd pwd

7 Comments

This just works for (the current) directory? If the target is a file, it will not give anything...
Doesn't work if the link is broken as you cannot make it your current path
To summarize with the benefit of hindsight: This answer works only in very limited circumstances, namely if the symlink of interest is to a directory that actually exists; plus, you must cd to it first, before calling pwd -P. In other words: it won't allow you to resolve (see the target of) symlinks to files or of broken symlinks, and for resolving existing-directory symlinks you have to do additional work (restore the previous working dir or localize the cd and pwd -P calls in a subshell).
to bad I look for a way to resolve a file and not a directory.
As others have pointed out, this doesn't really answer the question. @pixelbeat's answer below does.
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28

"pwd -P" seems to work if you just want the directory, but if for some reason you want the name of the actual executable I don't think that helps. Here's my solution:

#!/bin/bash # get the absolute path of the executable SELF_PATH=$(cd -P -- "$(dirname -- "$0")" && pwd -P) && SELF_PATH=$SELF_PATH/$(basename -- "$0") # resolve symlinks while [[ -h $SELF_PATH ]]; do # 1) cd to directory of the symlink # 2) cd to the directory of where the symlink points # 3) get the pwd # 4) append the basename DIR=$(dirname -- "$SELF_PATH") SYM=$(readlink "$SELF_PATH") SELF_PATH=$(cd "$DIR" && cd "$(dirname -- "$SYM")" && pwd)/$(basename -- "$SYM") done 

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23

One of my favorites is realpath foo

 realpath - return the canonicalized absolute pathname realpath expands all symbolic links and resolves references to '/./', '/../' and extra '/' characters in the null terminated string named by path and stores the canonicalized absolute pathname in the buffer of size PATH_MAX named by resolved_path. The resulting path will have no symbolic link, '/./' or '/../' components. 

4 Comments

On Debian (etch and later) this command is available in the realpath package.
realpath is now (Jan 2012) part of coreutils and backwards compatible with the debian and BSD variant
I don't have realpath on Centos 6 with GNU coreutils 8.4.31. I've come across several others on Unix & Linux that have a GNU coreutils packaged without realpath. So it seems to be dependent on more than just version.
I prefer realpath over readlink because it offers option flags such as --relative-to
10
readlink -e [filepath] 

seems to be exactly what you're asking for - it accepts an arbirary path, resolves all symlinks, and returns the "real" path - and it's "standard *nix" that likely all systems already have

1 Comment

Just got bitten by it. It doesn't work on Mac and I'm searching for replacement.
7

Another way:

# Gets the real path of a link, following all links myreadlink() { [ ! -h "$1" ] && echo "$1" || (local link="$(expr "$(command ls -ld -- "$1")" : '.*-> \(.*\)$')"; cd $(dirname $1); myreadlink "$link" | sed "s|^\([^/].*\)\$|$(dirname $1)/\1|"); } # Returns the absolute path to a command, maybe in $PATH (which) or not. If not found, returns the same whereis() { echo $1 | sed "s|^\([^/].*/.*\)|$(pwd)/\1|;s|^\([^/]*\)$|$(which -- $1)|;s|^$|$1|"; } # Returns the realpath of a called command. whereis_realpath() { local SCRIPT_PATH=$(whereis $1); myreadlink ${SCRIPT_PATH} | sed "s|^\([^/].*\)\$|$(dirname ${SCRIPT_PATH})/\1|"; } 

2 Comments

I need cd in myreadlink(), because it is a recursive function, going to each directory until it finds a link. If it finds a link, returns the realpath, and then sed would replace the path.
Better to change whereis() function to another name like mywhereis() to prevent override builtin command whereis.
5

Putting some of the given solutions together, knowing that readlink is available on most systems, but needs different arguments, this works well for me on OSX and Debian. I'm not sure about BSD systems. Maybe the condition needs to be [[ $OSTYPE != darwin* ]] to exclude -f from OSX only.

#!/bin/bash MY_DIR=$( cd $(dirname $(readlink `[[ $OSTYPE == linux* ]] && echo "-f"` $0)) ; pwd -P) echo "$MY_DIR" 

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4

Here's how one can get the actual path to the file in MacOS/Unix using an inline Perl script:

FILE=$(perl -e "use Cwd qw(abs_path); print abs_path('$0')") 

Similarly, to get the directory of a symlinked file:

DIR=$(perl -e "use Cwd qw(abs_path); use File::Basename; print dirname(abs_path('$0'))") 

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4

Update:

  • As of at least macOS 13 (Ventura), macOS now also supports readlink -f for following a symlink to its ultimate target (FreeBSD has had support for much longer), so the need for a POSIX-compliant solution has lessened considerably.

  • However, a POSIX-compliant solution - as implemented below - may still be of interest:

    • If you need to support older macOS versions and other Unix-like platforms where readlink -f is not implemented.

    • and/or you need consistent behavior across platforms:

      • Notably, readlink -f on macOS / FreeBSD is not equivalent to the GNU implementation (as found on Linux distros): -f on macOS / FreeBSD corresponds to GNU -e, which enforces the existence of the ultimate target (GNU's -f allows the last path segment of the ultimate target to be non-existent).

Below is a fully POSIX-compliant script / function that is therefore cross-platform (works on macOS too, whose readlink still doesn't support -f as of 10.12 (Sierra)) - it uses only POSIX shell language features and only POSIX-compliant utility calls.

It is a portable implementation of GNU's readlink -e (the stricter version of readlink -f).

You can run the script with sh or source the function in bash, ksh, and zsh:

For instance, inside a script you can use it as follows to get the running's script true directory of origin, with symlinks resolved:

trueScriptDir=$(dirname -- "$(rreadlink "$0")") 

rreadlink script / function definition:

The code was adapted with gratitude from this answer.
I've also created a bash-based stand-alone utility version here, which you can install with
npm install rreadlink -g, if you have Node.js installed.

#!/bin/sh # SYNOPSIS # rreadlink <fileOrDirPath> # DESCRIPTION # Resolves <fileOrDirPath> to its ultimate target, if it is a symlink, and # prints its canonical path. If it is not a symlink, its own canonical path # is printed. # A broken symlink causes an error that reports the non-existent target. # LIMITATIONS # - Won't work with filenames with embedded newlines or filenames containing # the string ' -> '. # COMPATIBILITY # This is a fully POSIX-compliant implementation of what GNU readlink's # -e option does. # EXAMPLE # In a shell script, use the following to get that script's true directory of origin: # trueScriptDir=$(dirname -- "$(rreadlink "$0")") rreadlink() ( # Execute the function in a *subshell* to localize variables and the effect of `cd`. target=$1 fname= targetDir= CDPATH= # Try to make the execution environment as predictable as possible: # All commands below are invoked via `command`, so we must make sure that # `command` itself is not redefined as an alias or shell function. # (Note that command is too inconsistent across shells, so we don't use it.) # `command` is a *builtin* in bash, dash, ksh, zsh, and some platforms do not # even have an external utility version of it (e.g, Ubuntu). # `command` bypasses aliases and shell functions and also finds builtins # in bash, dash, and ksh. In zsh, option POSIX_BUILTINS must be turned on for # that to happen. { \unalias command; \unset -f command; } >/dev/null 2>&1 [ -n "$ZSH_VERSION" ] && options[POSIX_BUILTINS]=on # make zsh find *builtins* with `command` too. while :; do # Resolve potential symlinks until the ultimate target is found. [ -L "$target" ] || [ -e "$target" ] || { command printf '%s\n' "ERROR: '$target' does not exist." >&2; return 1; } command cd "$(command dirname -- "$target")" # Change to target dir; necessary for correct resolution of target path. fname=$(command basename -- "$target") # Extract filename. [ "$fname" = '/' ] && fname='' # !! curiously, `basename /` returns '/' if [ -L "$fname" ]; then # Extract [next] target path, which may be defined # *relative* to the symlink's own directory. # Note: We parse `ls -l` output to find the symlink target # which is the only POSIX-compliant, albeit somewhat fragile, way. target=$(command ls -l "$fname") target=${target#* -> } continue # Resolve [next] symlink target. fi break # Ultimate target reached. done targetDir=$(command pwd -P) # Get canonical dir. path # Output the ultimate target's canonical path. # Note that we manually resolve paths ending in /. and /.. to make sure we have a normalized path. if [ "$fname" = '.' ]; then command printf '%s\n' "${targetDir%/}" elif [ "$fname" = '..' ]; then # Caveat: something like /var/.. will resolve to /private (assuming /var@ -> /private/var), i.e. the '..' is applied # AFTER canonicalization. command printf '%s\n' "$(command dirname -- "${targetDir}")" else command printf '%s\n' "${targetDir%/}/$fname" fi ) rreadlink "$@" 

A tangent on security:

jarno, in reference to the function ensuring that builtin command is not shadowed by an alias or shell function of the same name, asks in a comment:

What if unalias or unset and [ are set as aliases or shell functions?

The motivation behind rreadlink ensuring that command has its original meaning is to use it to bypass (benign) convenience aliases and functions often used to shadow standard commands in interactive shells, such as redefining ls to include favorite options.

I think it's safe to say that unless you're dealing with an untrusted, malicious environment, worrying about unalias or unset - or, for that matter, while, do, ... - being redefined is not a concern.

There is something that the function must rely on to have its original meaning and behavior - there is no way around that.
That POSIX-like shells allow redefinition of builtins and even language keywords is inherently a security risk (and writing paranoid code is hard in general).

To address your concerns specifically:

The function relies on unalias and unset having their original meaning. Having them redefined as shell functions in a manner that alters their behavior would be a problem; redefinition as an alias is not necessarily a concern, because quoting (part of) the command name (e.g., \unalias) bypasses aliases.

However, quoting is not an option for shell keywords (while, for, if, do, ...) and while shell keywords do take precedence over shell functions, in bash and zsh aliases have the highest precedence, so to guard against shell-keyword redefinitions you must run unalias with their names (although in non-interactive bash shells (such as scripts) aliases are not expanded by default - only if shopt -s expand_aliases is explicitly called first).

To ensure that unalias - as a builtin - has its original meaning, you must use \unset on it first, which requires that unset have its original meaning:

unset is a shell builtin, so to ensure that it is invoked as such, you'd have to make sure that it itself is not redefined as a function. While you can bypass an alias form with quoting, you cannot bypass a shell-function form - catch 22.

Thus, unless you can rely on unset to have its original meaning, from what I can tell, there is no guaranteed way to defend against all malicious redefinitions.

8 Comments

In my experience, quoting bypasses aliases, not shell functions, unlike you first tell.
I tested that I can define [ as an alias in dash and bash and as a shell function in bash.
I made my point as a separate question.
@jarno: You can define while as a function in bash, ksh, and zsh (but not dash), but only with function <name> syntax: function while { echo foo; } works (while() { echo foo; } doesn't). However, this wont' shadow the while keyword, because keywords have higher precedence than functions (the only way to invoke this function is as \while). In bash and zsh, aliases have higher precedence than keywords, so alias redefinitions of keywords do shadow them (but in bash by default only in interactive shells, unless shopt -s expand_aliases is explicitly called).
@Znik, please see the top section I've just added to the answer.
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3

Common shell scripts often have to find their "home" directory even if they are invoked as a symlink. The script thus have to find their "real" position from just $0.

cat `mvn` 

on my system prints a script containing the following, which should be a good hint at what you need.

if [ -z "$M2_HOME" ] ; then ## resolve links - $0 may be a link to maven's home PRG="$0" # need this for relative symlinks while [ -h "$PRG" ] ; do ls=`ls -ld "$PRG"` link=`expr "$ls" : '.*-> \(.*\)$'` if expr "$link" : '/.*' > /dev/null; then PRG="$link" else PRG="`dirname "$PRG"`/$link" fi done saveddir=`pwd` M2_HOME=`dirname "$PRG"`/.. # make it fully qualified M2_HOME=`cd "$M2_HOME" && pwd` 

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3

Is your path a directory, or might it be a file? If it's a directory, it's simple:

(cd "$DIR"; pwd -P) 

However, if it might be a file, then this won't work:

DIR=$(cd $(dirname "$FILE"); pwd -P); echo "${DIR}/$(readlink "$FILE")" 

because the symlink might resolve into a relative or full path.

On scripts I need to find the real path, so that I might reference configuration or other scripts installed together with it, I use this:

SOURCE="${BASH_SOURCE[0]}" while [ -h "$SOURCE" ]; do # resolve $SOURCE until the file is no longer a symlink DIR="$( cd -P "$( dirname "$SOURCE" )" && pwd )" SOURCE="$(readlink "$SOURCE")" [[ $SOURCE != /* ]] && SOURCE="$DIR/$SOURCE" # if $SOURCE was a relative symlink, we need to resolve it relative to the path where the symlink file was located done 

You could set SOURCE to any file path. Basically, for as long as the path is a symlink, it resolves that symlink. The trick is in the last line of the loop. If the resolved symlink is absolute, it will use that as SOURCE. However, if it is relative, it will prepend the DIR for it, which was resolved into a real location by the simple trick I first described.

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3

In case where pwd can't be used (e.g. calling a scripts from a different location), use realpath (with or without dirname):

$(dirname $(realpath $PATH_TO_BE_RESOLVED)) 

Works both when calling through (multiple) symlink(s) or when directly calling the script - from any location.

Comments

2
function realpath { local r=$1; local t=$(readlink $r) while [ $t ]; do r=$(cd $(dirname $r) && cd $(dirname $t) && pwd -P)/$(basename $t) t=$(readlink $r) done echo $r } #example usage SCRIPT_PARENT_DIR=$(dirname $(realpath "$0"))/.. 

5 Comments

This will break with (a) any path containing whitespace or shell metacharacters and (b) broken symlinks (not an issue with if you just want the running script's parent path, assuming (a) doesn't apply).
If you are concerned with whitespace use quotes.
Please do - although that won't address (b).
Please show me an example of b) where this fails. By definition, a broken symlink points to a directory entry that doesn't exist. The point of this script is to resolve symlinks in the other direction. If the symlink were broken you wouldn't be executing the script. This example is intended to demonstrate resolving the currently executing script.
"intended to demonstrate resolving the currently executing script" - indeed, which is a narrowing of the question's scope you've elected to focus on; that is perfectly fine, as long as you say so. Since you didn't, I stated it in my comment. Please fix the quoting issue, which is a problem irrespective of the scope of the answer.
2

This is a symlink resolver in Bash that works whether the link is a directory or a non-directory:

function readlinks {( set -o errexit -o nounset declare n=0 limit=1024 link="$1" # If it's a directory, just skip all this. if cd "$link" 2>/dev/null then pwd -P return 0 fi # Resolve until we are out of links (or recurse too deep). while [[ -L $link ]] && [[ $n -lt $limit ]] do cd "$(dirname -- "$link")" n=$((n + 1)) link="$(readlink -- "${link##*/}")" done cd "$(dirname -- "$link")" if [[ $n -ge $limit ]] then echo "Recursion limit ($limit) exceeded." >&2 return 2 fi printf '%s/%s\n' "$(pwd -P)" "${link##*/}" )} 

Note that all the cd and set stuff takes place in a subshell.

4 Comments

Actually, the { } around the ( ) are unnecessary, since ( ) counts as a "compound command", just like { }. But you still need () after the function name.
@ChrisCogdon The {} around the () are not unnecessary if there are no () behind the function name. Bash accepts function declarations without () because shell does not have parameter lists in declarations and doesn't do calls with () so function declarations with () don't make a lot of sense.
This will break if symlink has paths in it, e.g., ../dir1/dir2/file
Can you give an example of a setup where it broke? It ultimately prints the physical path (pwd -P) so I'm not sure you mean by broken; it won't always be the shortest possible way to print the path.
1

Try this:

cd $(dirname $([ -L $0 ] && readlink -f $0 || echo $0)) 

Comments

1

Since I've run into this many times over the years, and this time around I needed a pure bash portable version that I could use on OSX and linux, I went ahead and wrote one:

The living version lives here:

https://github.com/keen99/shell-functions/tree/master/resolve_path

but for the sake of SO, here's the current version (I feel it's well tested..but I'm open to feedback!)

Might not be difficult to make it work for plain bourne shell (sh), but I didn't try...I like $FUNCNAME too much. :)

#!/bin/bash resolve_path() { #I'm bash only, please! # usage: resolve_path <a file or directory> # follows symlinks and relative paths, returns a full real path # local owd="$PWD" #echo "$FUNCNAME for $1" >&2 local opath="$1" local npath="" local obase=$(basename "$opath") local odir=$(dirname "$opath") if [[ -L "$opath" ]] then #it's a link. #file or directory, we want to cd into it's dir cd $odir #then extract where the link points. npath=$(readlink "$obase") #have to -L BEFORE we -f, because -f includes -L :( if [[ -L $npath ]] then #the link points to another symlink, so go follow that. resolve_path "$npath" #and finish out early, we're done. return $? #done elif [[ -f $npath ]] #the link points to a file. then #get the dir for the new file nbase=$(basename $npath) npath=$(dirname $npath) cd "$npath" ndir=$(pwd -P) retval=0 #done elif [[ -d $npath ]] then #the link points to a directory. cd "$npath" ndir=$(pwd -P) retval=0 #done else echo "$FUNCNAME: ERROR: unknown condition inside link!!" >&2 echo "opath [[ $opath ]]" >&2 echo "npath [[ $npath ]]" >&2 return 1 fi else if ! [[ -e "$opath" ]] then echo "$FUNCNAME: $opath: No such file or directory" >&2 return 1 #and break early elif [[ -d "$opath" ]] then cd "$opath" ndir=$(pwd -P) retval=0 #done elif [[ -f "$opath" ]] then cd $odir ndir=$(pwd -P) nbase=$(basename "$opath") retval=0 #done else echo "$FUNCNAME: ERROR: unknown condition outside link!!" >&2 echo "opath [[ $opath ]]" >&2 return 1 fi fi #now assemble our output echo -n "$ndir" if [[ "x${nbase:=}" != "x" ]] then echo "/$nbase" else echo fi #now return to where we were cd "$owd" return $retval } 

here's a classic example, thanks to brew:

%% ls -l `which mvn` lrwxr-xr-x 1 draistrick 502 29 Dec 17 10:50 /usr/local/bin/mvn@ -> ../Cellar/maven/3.2.3/bin/mvn 

use this function and it will return the -real- path:

%% cat test.sh #!/bin/bash . resolve_path.inc echo echo "relative symlinked path:" which mvn echo echo "and the real path:" resolve_path `which mvn` %% test.sh relative symlinked path: /usr/local/bin/mvn and the real path: /usr/local/Cellar/maven/3.2.3/libexec/bin/mvn 

1 Comment

My earlier answer does exactly the same thing in about 1/4 of the space :) It's pretty basic shell scripting and not worthy of a git repo.
1

To work around the Mac incompatibility, I came up with

echo `php -r "echo realpath('foo');"` 

Not great but cross OS

5 Comments

Python 2.6+ is available on more end-user systems than php, so python -c "from os import path; print(path.realpath('${SYMLINK_PATH}'));" would probably make more sense. Still, by the time you need to use Python from a shell script, you should probably just use Python and save yourself the headache of cross platform shell scripting.
You don't need any more than the sh built-ins readlink, dirname and basename.
@Dave: dirname, basename, and readlink are external utilities, not shell built-ins; dirname and basename are part of POSIX, readlink is not.
@mklement0 - You are quite right. They are provided by CoreUtils or equivalent. I shouldn't visit SO after 1am. The essence of my comment is that neither PHP nor any other language interpreter beyond that installed in a base system are required. I have used the script I provided on this page on every linux variant since 1997 and MacOS X since 2006 without error. The OP didn't ask for a POSIX solution. Their specific environment was Mac OS X.
@Dave: Yes, it is possible to do it with stock utilities, but it is also hard to do so (as evidenced by the shortcomings of your script). If OS X were truly the focus, then this answer is perfectly fine - and much simpler - given that php comes with OS X. However, even though the body of the question mentions OS X, it is not tagged as such, and it's become clear that people on various platforms come here for answers, so it's worth pointing out what's platform-specific / non-POSIX.
0

Here I present what I believe to be a cross-platform (Linux and macOS at least) solution to the answer that is working well for me currently.

crosspath() { local ref="$1" if [ -x "$(which realpath)" ]; then path="$(realpath "$ref")" else path="$(readlink -f "$ref" 2> /dev/null)" if [ $? -gt 0 ]; then if [ -x "$(which readlink)" ]; then if [ ! -z "$(readlink "$ref")" ]; then ref="$(readlink "$ref")" fi else echo "realpath and readlink not available. The following may not be the final path." 1>&2 fi if [ -d "$ref" ]; then path="$(cd "$ref"; pwd -P)" else path="$(cd $(dirname "$ref"); pwd -P)/$(basename "$ref")" fi fi fi echo "$path" } 

Here is a macOS (only?) solution. Possibly better suited to the original question.

mac_realpath() { local ref="$1" if [[ ! -z "$(readlink "$ref")" ]]; then ref="$(readlink "$1")" fi if [[ -d "$ref" ]]; then echo "$(cd "$ref"; pwd -P)" else echo "$(cd $(dirname "$ref"); pwd -P)/$(basename "$ref")" fi } 

Comments

0

My answer here Bash: how to get real path of a symlink?

but in short very handy in scripts:

script_home=$( dirname $(realpath "$0") ) echo Original script home: $script_home 

These are part of GNU coreutils, suitable for use in Linux systems.

To test everything, we put symlink into /home/test2/, amend some additional things and run/call it from root directory:

/$ /home/test2/symlink /home/test Original script home: /home/test 

Where

Original script is: /home/test/realscript.sh Called script is: /home/test2/symlink 

Comments

0

This is the best solution, tested in Bash 3.2.57:

# Read a path (similar to `readlink`) recursively, until the physical path without any links (like `cd -P`) is found. # Accepts any existing path, prints its physical path and exits `0`, exits `1` if some contained links don't exist. # Motivation: `${BASH_SOURCE[0]}` often contains links; using it directly to extract your project's path may fail. # # Example: Safely `source` a file located relative to the current script # # source "$(dirname "$(rreadlink "${BASH_SOURCE[0]}")")/relative/script.sh" #Inspiration: https://stackoverflow.com/a/51089005/6307827 rreadlink () { declare p="$1" d l while :; do d="$(cd -P "$(dirname "$p")" && pwd)" || return $? #absolute path without symlinks p="$d/$(basename "$p")" if [ -h "$p" ]; then l="$(readlink "$p")" || break #A link must be resolved from its fully resolved parent dir. d="$(cd "$d" && cd -P "$(dirname "$l")" && pwd)" || return $? p="$d/$(basename "$l")" else break fi done printf '%s\n' "$p" } 

Comments

-1

My 2 cents. This function is POSIX compliant, and both the source and the destination can contain ->. However, I have not gotten it work with filenames that container newline or tabs, as ls in general has issues with those.

resolve_symlink() { test -L "$1" && ls -l "$1" | awk -v SYMLINK="$1" '{ SL=(SYMLINK)" -> "; i=index($0, SL); s=substr($0, i+length(SL)); print s }' } 

I believe the solution here is the file command, with a custom magic file that only outputs the destination of the provided symlink.

1 Comment

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