Data variable in jquery ajax function

Question

I'm trying to use the code below, but it's not working: UPDATED WORKING:

$(document).ready(function() { $('.infor').click(function () { var datasend = $(this).html(); $.ajax({ type: 'POST', url: 'http://domain.com/page.php', data: 'im_id='+datasend', success: function(data){ $('#test_holder').html(data); } }); }); });

As you can see I used $datasend as the var to send but it doesn't return the value of it, only its name.

Saigework · Accepted Answer · 2011-11-05 21:17:25Z

3

I would change $datasend = $(this).html; to var datasend = $(this).html();

Next I would change data: 'im_id=$datasend', to data: 'im_id='+datasend,

answered Nov 5, 2011 at 21:17

Saigework

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2 Comments

elbatron Over a year ago

How could I pass another variable in the data line? Fox example something like this: 'im_id='+datasend&'ot_id='+data2send

Saigework Over a year ago

All you have to do is concatenate them (if you want to use that route) together. There are some quote problems with your code block above. 'im_id='+datasend+'&ot_id='+data2send In the long run you may want to assign all of this data to an array and then POST the array rather than build a giant string.

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