Multiple data variables in jquery ajax function

Question

Yesterday I had question (answered), which I have to expand a bit more today. I need to pass two or more variables, but I can't find the proper syntax: UPDATED, WORKING CODE:

$(document).ready(function() { $('.infor').click(function () { var datasend = $(this).html(); var datasendmore = $(this).next().html(); $.ajax({ type: 'POST', url: 'http://domain.com/page.php', data: {im_id:datasend, yt_id:datasendmore}, success: function(data){ $('#test_holder').html(data); } }); }); });

Thanks.

Does .next work in this way or is it .next() that you need?

MyStream
– MyStream

2011-11-06 09:42:30 +00:00
Commented Nov 6, 2011 at 9:42 — MyStream
– MyStream, Commented Nov 6, 2011 at 9:42
Right, updated above the snippet again.

elbatron
– elbatron

2011-11-07 16:26:56 +00:00
Commented Nov 7, 2011 at 16:26 — elbatron
– elbatron, Commented Nov 7, 2011 at 16:26

Mike · Accepted Answer · 2011-11-06 09:34:16Z

3

use:

data: {im_id:datasend,yt_id:datasendmore}

answered Nov 6, 2011 at 9:34

Mike

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1 Comment

elbatron Over a year ago

That was quick. I updated my question with the correct syntax.

MyStream · Accepted Answer · 2011-11-06 09:40:38Z

There is one minor typo:

data: 'im_id='+datasend','

should be

data: 'im_id='+datasend+',

From what I can see above.

and I'd use {im_id: value1, param2:value2, param3:value3 etc}

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