How to register an app to respond to a custom URL scheme opening request?

Question

Like this:

NSString *stringURL = @"appname://"; NSURL *url = [NSURL URLWithString:stringURL]; [[UIApplication sharedApplication] openURL:url];

I slightly remember it was necessary to write a value-key to Info.plist. How?

You could see a detailed illustration with the updated 2015 version for Xcode 6 here stackoverflow.com/a/18480723/1780492 — BootMaker
– BootMaker, Commented May 24, 2015 at 8:16

d.lebedev · Accepted Answer · 2011-11-20 12:32:05Z

7

Add this to plist screenshot .

The app will by called by @"readtext://" url

answered Nov 20, 2011 at 12:32

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1 Comment

Xcode 4 looks completely different! Must I really repeat the bundle identifier for the URL type? It also asks for an Icon and Role.

Community · Accepted Answer · 2017-05-23 12:25:42Z

1

This seems to be the question that I answered (with screenshots & source code) here.

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And I've posted a full walkthrough of how to do this on my blog.

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answered Apr 28, 2014 at 7:10

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You're welcome. It's simple, isn't it, once you can see an example ? It turns a two-hour headache into a 5-minute job !!