My current regular expression should be correct, though I wouldn't expect so, it doesn't work properly. It won't return "Got Match" My currrent code is as follows:
$id = "http://steamcommunity.com/id/TestID"; if (preg_match("^http://steamcommunity\.com/id/.*?\n$", $id)) { print "Got match!\n"; } You're missing delimiters on your regex:
if (preg_match("#^http://steamcommunity\.com/id/.*?\n$#", $id)) { ^--here ^--here Note that I've used # as the delimiter here, since that saves you having to escape all of the internal / charrs, if you'd used the traditional / as the delimiter.
You need a delimiter, like this:
if (preg_match("#^http://steamcommunity\.com/id/.*?$#", $id)) { ^ ^ And what's with the newline at the end? Surely you don't need that.
/ inside the url, which is required if you use / as the delimiter.
You're missing delimiters. For example:
"#^http://steamcommunity\.com/id/.*?\n$#" Also, you're trying to match a newline (\n) that isn't in your string.
You need to add the pattern delimiter:
$id = "http://steamcommunity.com/id/TestID"; if (preg_match("#^http://steamcommunity\.com/id/.*?(\n|$)#", $id)) { print "Got match!\n"; } There are a couple of things that are wrong with it. First of all, you need to delimit the start and end of your regex with a character. I used #. You're also matching for a new line at the end of your regex, which you don't have and likely won't ever have in your string.
<?php $id = "http://steamcommunity.com/id/TestID"; if (preg_match("#^http://steamcommunity\.com/id/.*?$#", $id)) { print "Got match!\n"; } ?> First of all, your regex shouldn't even compile because it's missing delimiters.
if (preg_match("~^http://steamcommunity\.com/id/.*?\n$~", $id)) { ^---- these guys here -----^ Second of all, why do you have a \n if your string doesn't contain a new line?
And finally, why are you using regex at all? Effectively, you are just trying to match a constant string. This should be equivalent to what you are trying to match:
if (strpos($id, 'http://steamcommunity.com/id/') === 0) { 
You need to have starting and ending delimiter in your pattern like /pattern/ or #pattern# or with brackets (pattern). Why is that? To have some pattern modifiers after ending delimiter like #pattern#i (ignore case)
preg_match('(^http://steamcommunity\.com/id/.*?\n$)', $id) As the say your patten is start and end wrong. (Delimiter)
But this will be a better match of a 64-bit Steam ID. (Minimum 17 and Maximum 25 numbers)
if( preg_match("#^http://steamcommunity\.com/id/([0-9]{17,25})#i", $id, $matches) ) { echo "Got match! - ".$matches; } I believe that there is no need for you to require that the string must end with a line break.
Explanation.
http://steamcommunity\.com/id/([0-9]{17,25}) ^--- string ---^^-- Regexp --^ [0-9] - Match a number between 0 to 9
{17,25} - Make 17 to 25 matches
() - Returns match
Or use pattern as those (It is the same):
/^http:\/\/steamcommunity\.com\/id\/([0-9]{17,25})/i (^http://steamcommunity\.com/id/([0-9]{17,25}))i Regular Expressions PHP Tutorial
Online regular expression testing <- Dont use delimiter.
<?php # URL that generated this code: # http://txt2re.com/index-php.php3?s=http://steamcommunity.com/id&-1 $txt='http://steamcommunity.com/id'; $re1='(http:\\/\\/steamcommunity\\.com\\/id)'; # HTTP URL 1 if ($c=preg_match_all ("/".$re1."/is", $txt, $matches)) { $httpurl1=$matches[1][0]; print "($httpurl1) \n"; } #----- # Paste the code into a new php file. Then in Unix: # $ php x.php #----- ?> Resorces: http://txt2re.com/index.php3?s=http://steamcommunity.com/id&-1
