Passing data between deferred functions

Question

I'm using some deferred functions with the .done so, I'm having something like that:

askTime(number).done(formatTime).done(function(html){ times += html; });

But although formatTime returns data, the html var has the data returned by askTime.

I don't know where if the problem. formatTime receives a data variable which is returned by askTime but if I put:

askTime(number).done(formatTime(data)).done(function(html)

It says that data isn't defined.

Try askTime(number).done(function(data) {formatTime(data);}).done(function(html) — hungryMind
– hungryMind, Commented Dec 2, 2011 at 13:42
Inconsistency in Q, But although formatTime returns data & formatTime receives a data variable. Code for askTIme, formatTime will help. — hungryMind
– hungryMind, Commented Dec 2, 2011 at 13:44
@hungryMind both functions works since both were part of the same function I splitted to be able to use them elsewhere. — Antonio Laguna
– Antonio Laguna, Commented Dec 2, 2011 at 13:48
@hungryMind also, your first try (although) seemed logicall to me, didn't work :( — Antonio Laguna
– Antonio Laguna, Commented Dec 2, 2011 at 13:51

jAndy · Accepted Answer · 2011-12-02 13:42:58Z

2

To chain deferred methods, you need to invoke .pipe().

Have a look: http://api.jquery.com/deferred.pipe/

answered Dec 2, 2011 at 13:42

jAndy

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4 Comments

Antonio Laguna Over a year ago

I'm having a look but unable to understand correctly. Examples given are a bit hard or unclear (for me at least)

Pointy Over a year ago

@AntonioLaguna Just try ".pipe()" instead of the first ".done()" in your code.

Antonio Laguna Over a year ago

I picked up the final code from here stackoverflow.com/questions/5921283/… and works and seems to understandable to me but this is not exactly what comes in the docs. Could you give me more light please?

Antonio Laguna Over a year ago

Thanks again @jAndy you seem to be a master of the deferred!

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