I want to generate alphanumeric unique numbers but the format should be like this
that should be starts from AA001 to AA999 after that AB001 to AB999 .... BA001 to BA999 end with ZZ999. if i give the input is
1 = result AA001 999 = result AA999 1000 = result AB001 any one can help this ?
Complete solution (see it running):
function formatNum1000($num) { $tail = $num % 1000; $head = (int)($num / 1000); $char1 = chr(ord('A') + (int)($head / 26)); $char2 = chr(ord('A') + ($head % 26)); return sprintf('%s%s%03d', $char1, $char2, $tail); } function formatNum999($num) { $tail = (($num - 1 ) % 999) + 1; $head = (int)(($num - $tail) / 999); $char1 = chr(ord('A') + (int)($head / 26)); $char2 = chr(ord('A') + ($head % 26)); return sprintf('%s%s%03d', $char1, $char2, $tail); } $ns = array(1, 500, 999, 1000, 1998, 1999, 2000, 25974, 25975, 25999, 26000, 675324, 675999); foreach($ns as $n) { $formatted1000 = formatNum1000($n); $formatted999 = formatNum999 ($n); echo "Num: $n => $formatted1000 / $formatted999\n"; } Note: you need to make sure that the input number is within the valid range (0...675999 when including 000-numbers, 1...675324 otherwise)
Note: answer revised, missed the point earlier that 000 is not allowed
How about:
$start = 'AA997'; for($i = 0; $i < 5; $i++) { $start++; if (substr($start, 2) == '000') continue; echo $start,"\n"; } output:
AA998 AA999 AB001 AB002 
result AB000for1000?