How to print the current user and system name in Unix?

Question

Please i am looking forward to learn how to print the current logged-in user and system name in Unix.

#include <unistd.h> #include <fcntl.h> using namespace std; int main(int argc, char **argv) { //Print the current logged-in user / username. //Print the name of the system / computer name. return 0; }

I would be grateful if you can provide a line of code or two as demonstration. Thanks

Is this a home work question? You should probably do some research rather than ask something like this straight out. See en.wikipedia.org/wiki/Exec_(operating_system) for instance. — Matt Lacey
– Matt Lacey, Commented Jan 4, 2012 at 8:29

fge · Accepted Answer · 2012-01-04 08:30:40Z

5

User --> getuid() (see also geteuid()).

Machine name --> gethostname().

That is pure C. I don't know whether C++ has other library calls for that.

answered Jan 4, 2012 at 8:30

fge

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1 Comment

Keith Thompson Over a year ago

I wouldn't call it "pure C". The functions are defined by POSIX, not by the C standard, and they might not be available on some systems (Windows, for example). (Yes, I know the question is tagged "unix".)

Basile Starynkevitch · Accepted Answer · 2012-01-04 08:32:03Z

You need to call the uname, gethostname, getuid (and perhaps getgid) system calls, and to convert the numerical uid with getpwent function.

codaddict · Accepted Answer · 2012-01-04 08:37:25Z

getuid() gets the id not the username. To get the username you'll have to additionally use getpwuid():

struct passwd *passwd; passwd = getpwuid ( getuid()); printf("The Login Name is %s ", passwd->pw_name);

See it

And for getting the hostname you can use the gethostname() function.

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