So I'm not to OOP in PHP.
Here is my issue I have a object that I can call a function from and it provides back an arrary. So here is the code.
$obj = new OBJ(); function go($url){ $array = $obj->grabArray($url); echo $array['hits']; } go('http://www.mysite.com/hello'); This gives me the error
Fatal error: Call to a member function grabArray() on a non-object
This is not an OOP issue, it's a scope issue. $obj isn't visible inside the function go(). You either need to pass it in as a parameter, or bring it into the function's scope with the global keyword (not recommended)
Recommended way
$obj = new OBJ(); go('http://www.mysite.com/hello', $obj); function go( $url, $object ) { $array = $object->grabArray($url); echo $array['hits']; } Not Recommended way
$obj = new OBJ(); go('http://www.mysite.com/hello'); function go( $url ) { global $obj; $array = $object->grabArray($url); echo $array['hits']; } There's another solution which is similar to the OOP concept of composition - you would make the go() function responsible for creating an instance of OBJ.
go('http://www.mysite.com/hello'); function go( $url ) { $obj = new OBJ(); $array = $obj->grabArray($url); echo $array['hits']; } This is probably not ideal, though, since you'd create a brand new OBJ instance every time you executed go(). You could fix this by "caching" the instance of OBJ inside go() with a static variable
function go( $url ) { static $obj; if ( is_null( $obj ) ) { $obj = new OBJ(); } $array = $obj->grabArray($url); echo $array['hits']; } But this composition-like approach is really only useful if you don't use your instance of OBJ anywhere else besides inside the go() function - if you do use it elsewhere, then the parameter approach is the best choice.
It's all about picking the right solution for the task at hand!
