97

Having a XML document like this:

<?xml version="1.0" encoding="UTF-8"?> <records type="array"> <record> <name>svn</name> <record-type>A</record-type> <ttl type="integer">86400</ttl> <zone-id type="integer">69075</zone-id> <aux type="integer">0</aux> <id type="integer">xxx</id> <active>Y</active> <data>xxx.xxx.xxx.xxx</data> </record> <record> <name>domain.tld.</name> <record-type>NS</record-type> <ttl type="integer">86400</ttl> <zone-id type="integer">xxx</zone-id> <aux type="integer">0</aux> <id type="integer">xxx</id> <active>Y</active> <data>domain.tld.</data> </record> <record> <name>blog</name> <record-type>A</record-type> <ttl type="integer">86400</ttl> <zone-id type="integer">xxx</zone-id> <aux type="integer">0</aux> <id type="integer">xxx</id> <active>Y</active> <data>xxx.xxx.xxx.xxx</data> </record> </records>

How to match all the /records/record/name having as sibling /records/record/record-type with the value A?

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3 Answers 3

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112

Found it:

/records/record/name[../record-type/text() = "A"]
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1 Comment

It's simpler and clearer to test record before descending to name.
69

Surprisingly, none of the answers to date on this old question provide the simplest XPath solution.

This simple XPath

/records/record[record-type = "A"]/name

selects

<name>svn</name> <name>blog</name>

as requested.

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Comments

38

You can also filter a parent element by its children :

/records/record[record-type[text()='A']]/name

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1 Comment

It's simpler and clearer to test record-type directly without an additional predicate.

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