how to check strings array's 1st elements 1st symbol with if?

Question

So basically I got string array, lets say a[i][b];

so the code looks something like this -

for(int i = 0; i < 3; i++) { for(int n = 0; b < 3; b++) { if(a[i][b] == "s") { cout << a[i][b] << endl; } } }

the array exists, and I can check it if I just show on console the a[i][b] without if statement, but with if statement it gives me this error -

error: ISO C++ forbids comparison between pointer and integer

Is there any way to fix that?

where is n coming into this? can you give us all of the code? — SD1990
– SD1990, Commented Feb 21, 2012 at 14:12
Of what type is a? If it is a char**, you might want to check against a single character in your if condition, e.g. if(a[i][b]=='s') — Alex P.
– Alex P., Commented Feb 21, 2012 at 14:12

BoBTFish · Accepted Answer · 2012-02-21 14:13:07Z

5

"s" is a string literal, i.e. a character array, so decays to a pointer. To just compare to a character, use single quotes:

if (a[i][b]=='s')

answered Feb 21, 2012 at 14:13

BoBTFish

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1 Comment

user1223540 Over a year ago

That worked, lol thanks! Will accepted as soon as I will be able to!

Karoly Horvath · Accepted Answer · 2012-02-21 14:13:32Z

3

"s" is a C string literal, if you want to compare with a character use 's'.

answered Feb 21, 2012 at 14:13

Karoly Horvath

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Comments

shift66 · Accepted Answer · 2012-02-21 14:28:23Z

put s in single quotes like this 's'
"s" is a text and in C++ there is no String class (native). So "s" is actually a pointer to character sequence and a[i][b] is just a single character.

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