List modification in a loop

Question

I'm a newcomer to Python but I understand that things should not be done this way, so please consider the following code snippets as purely educational :-)

I'm currently reading 'Learning Python' and trying to fully understand the following example:

>>> L = [1, 2, 3, 4, 5] >>> for x in L: ... x += 1 ... >>> L [1, 2, 3, 4, 5]

I did not understand if this behavior was somewhat related to the immutability of the numeric types, so I've run the following test:

>>> L = [[1], [2], [3], [4], [5]] >>> for x in L: ... x += ['_'] ... >>> L [[1, '_'], [2, '_'], [3, '_'], [4, '_'], [5, '_']]

Question: what makes the list unchanged in the first code and changed in the second ?

My intuition is that the syntax is misleading and that:

x += 1 for an integer really means x = x + 1 (thus assigning a new reference)
x += ['_'] for a list really means x.extend('_') (thus changing the list in place)

and for completeness, the "correct" way to do this is [x+1 for x in L] — Kimvais
– Kimvais, Commented Mar 28, 2012 at 12:17
L = [x+1 for x in L] if you don't want a new list, then :) — Kimvais
– Kimvais, Commented Mar 28, 2012 at 12:28
@Kimvais: That still creates a new list, it's just setting L to refer to the new list. — MattH
– MattH, Commented Mar 28, 2012 at 12:45

MattH · Accepted Answer · 2012-03-28 12:25:01Z

Question: what makes the list unchanged in the first code and changed in the second ?

In the first code, the list is a sequence of (immutable) integers. The loop sets x to refer to each element of the sequence in turn. x += 1 changes x to refer to a different integer that is one more than the value x previously referred to. The element in the original list is unchanged.

In the second code, the list if a sequence of (mutable) lists. The loop sets x to refer to each element of the sequence in turn. x += ['_'] as x refers to a list, this extends the list referred to by x with ['_'].

Collectives™ on Stack Overflow

List modification in a loop

1 Answer 1

Comments

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Related