Is there a modulo function in the Python math library?
Isn't 15 % 4, 3? But 15 mod 4 is 1, right?
- 63 equals 15 mod 4.Paul Fisher– Paul Fisher2009-06-13 17:02:17 +00:00Commented Jun 13, 2009 at 17:02
- 2You're probably thinking that (15 mod 4 = -1) which is the same as saying (15 mod 4 = 3)Nathan Fellman– Nathan Fellman2009-06-13 17:03:53 +00:00Commented Jun 13, 2009 at 17:03
- 20Beware: (-41) % 3 == -2 in C, but (-41) % 3 == 1 in Python stackoverflow.com/questions/828092/…jfs– jfs2009-06-13 18:19:09 +00:00Commented Jun 13, 2009 at 18:19
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7 Answers
There's the % sign. It's not just for the remainder, it is the modulo operation.
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you can also try divmod(x, y) which returns a tuple (x // y, x % y)
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>>> 15 % 4 3 >>> The modulo gives the remainder after integer division.
answered Jun 13, 2009 at 17:06
Bill the Lizard
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mod = a % b
This stores the result of a mod b in the variable mod.
And you are right, 15 mod 4 is 3, which is exactly what python returns:
>>> 15 % 4 3 a %= b is also valid.
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Why don't you use % ?
print 4 % 2 # 0 
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I don't think you're fully grasping modulo. a % b and a mod b are just two different ways to express modulo. In this case, python uses %. No, 15 mod 4 is not 1, 15 % 4 == 15 mod 4 == 3.
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A = [3, 1, 2, 4] for a in A: print(a % 2) output:
1 1 0 0 