Say I have some command that outputs a bunch of strings. The output from this command could look something like:
... foo bar blargh ... Say I have some set string
myString$Blah I want to insert each of the strings where the $ is in the output of the command such that I end up with a file that looks like this:
... myStringfooBlah myStringbarBlah myStringblarghBlah ... What is the easiest way to accomplish this? (Awk and sed preferred)
You don't even need sed or awk.
xargs can do this: with: -L1 -I '$' echo 'myString$Blah'
$ cat x.list foo bar blargh $ cat x.list | tr '\n' '\0' | xargs -0 -L1 -I '$' echo 'myString$Blah' myStringfooBlah myStringbarBlah myStringblarghBlah You can do this completely in the shell (bash, at least) without too much trouble. Here's a script that does that:
#!/bin/bash pattern="$1" input_file="$2" output_file="$3" saved_IFS="$IFS" IFS=$'\n' # Store each line of the input file into an array named 'lines'. lines=($(< $input_file)) IFS="$saved_IFS" # Truncate output file, if any. cat /dev/null > $output_file # Substitute each line into the pattern, and write to output file. for ln in "${lines[@]}" do echo ${pattern/$/$ln} >> $output_file done Supposing this script is called script, and you have a file called in.txt with one string per line, then running script in.txt out.txt would give you the desired output in out.txt.
Assuming you can use the format string myString&Blah, with an ampersand instead of the dollar sign, pipe your output into this:
sed "s/.*/$format/" This works because the & is used as an "insert match here" operator in the replacement string. The regex matches the entire line, so it will insert the whole line at the &.
It is important to use the double quotes to allow expansion of the format string.
If you really need to use the ampersand, use this:
sed "s/.*/$(echo "$format" | tr '$' '&')/" The quotes around $format are important if you have whitespace in the string.
