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In Latex 3 I would like to be write a macro which takes as an argument code which can internally define a macro. How do I do this in a way that allows the code being passed to access arguments of the original. For example I would like to be able to do something like the following. 

\documentclass{article} \usepackage{xparse, expl3} \begin{document} \DeclareDocumentCommand{\CodeMacro}{m +m} { Do Something #2 } \CodeMacro{Test} { \DeclareDocumentCommand\csname Testing#1\endcsname{m} { #1-##1 } } \end{document}

I would like this to expand to 

Do Something \DeclareDocumentCommand\csname TestingTest\endcsname{m} { Test-#1 }
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    \expandafter\DeclareDocumentCommand\csname Testing#1\endcsname{}, but you should think about whether this is needed at all. By the way, xparse loads expl3 already and on document level, you don't use LaTeX 3 code at all at the moment Commented Jul 5, 2017 at 16:37
  • Just curiosity or do you have some application in mind? Commented Jul 5, 2017 at 17:04

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You shouldn't be using \DeclareDocumentCommand to begin with; the command has its uses, but in general you should prefer \NewDocumentCommand.

What you seem to need is a function like \NewNamedDocumentCommand, plus some dirty trick.

\documentclass{article} \usepackage{expl3,xparse} \ExplSyntaxOn % or spaces would count \NewDocumentCommand{\CodeMacro}{m +m} { Do Something \nate_do:nn {#1}{#2} } \NewDocumentCommand{\NewNamedDocumentCommand}{mmm} { \exp_args:Nc \NewDocumentCommand{#1}{#2}{#3} } \cs_new_protected:Nn \nate_do:nn { \cs_set_protected:Nn \__nate_do:n { #2 } \__nate_do:n { #1 } } \ExplSyntaxOff \begin{document} \CodeMacro{Test}{% \NewNamedDocumentCommand{Testing#1}{m}{% #1-##1% }% } \TestingTest{X} \end{document}

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