3

I have a beamer frame which for some reasons I want to be with the allowframebreaks option (to have the frame title counter). I have multiple theorem boxes and a tikZ picture (inside a figure environment) on this frame, which spread over 2 pages. Now comes the fun part: I want to add \pause between some of the content to reveal it bit by bit, but this seems to mess it up, which I kind of understand, since it's technically still only one frame showing on multiple slides from the frame break and the pause at the same time... Does anyone have a better idea how to do this, or can tell me if this is even possible? Thanks heaps F

 \documentclass{beamer} \usetheme{CambridgeUS} \usecolortheme{seahorse} \usepackage[utf8]{inputenc} \usepackage[english]{babel} \usepackage[T1]{fontenc} \usepackage{amsmath} \usepackage{amsfonts} \usepackage{amssymb} \usepackage{csquotes} \usepackage{graphicx} \usepackage{pgfplots} \setbeamertemplate{theorems}[ams style] \begin{document} \begin{frame}[allowframebreaks]{Theorems} \begin{theorem} Suppose $|I|\geq3$ and $\Theta$ is \textbf{rich}:\\ For any $i,~\theta'_i,~\theta_i$, manipulation $\theta'_i$ is an \textbf{OM} for $\theta_i$ under mechanism $\phi\iff$ for any mechanism $\psi$ \textbf{i-undistinguishable} from $\phi,~\theta'_i$ is a \textbf{profitable} manipulation for $\theta_i$ \end{theorem} %\pause \begin{figure} \centering \scalebox{.75}{\input{Plot1.tex}} %see my previous question %\caption{} %\label{fig:f1} \end{figure} %\pause \begin{theorem} Any stable-dominating mechanism is \textbf{not obviously manipulable} \end{theorem} %\pause \begin{theorem} Any stable mechanism is individually rational, Pareto efficient, and \textbf{not obviously manipulable} \end{theorem} %\pause \begin{theorem} The $(K+1)$-price auction is \textbf{not obviously manipulable} \end{theorem} %\pause \begin{theorem} Every efficient, individually rational, and weakly budget balanced mechanism is \textbf{obviously manipulable} \end{theorem} \end{frame} \end{document}
Improve this question
2
  • Are you sure, the contents will all fit onto just 2 slides? Commented Jan 8, 2020 at 10:24
  • Yep, it does. It's tight, but it fits! ;-) Commented Jan 8, 2020 at 10:31

1 Answer 1

Reset to default
4

To quote from the beamer user guide:

You can use the option allowframebreaks to cause the ⟨frame text⟩ to be split among several slides, though you cannot use overlays then. (See p. 59)

and:

The use of this option is evil. In a (good) presentation you prepare each slide carefully and think twice before putting something on a certain slide rather than on some different slide. Using the allowframebreaks option invites the creation of horrible, endless presentations that resemble more a “paper projected on the wall” than a presentation. Nevertheless, the option does have its uses. Most noticeably, it can be convenient for automatically splitting bibliographies or long equations.

As a consequence, I'd manually split the contents into 3 slides as follows:

\documentclass{beamer} \usetheme{CambridgeUS} \usecolortheme{seahorse} \usepackage[utf8]{inputenc} \usepackage[english]{babel} \usepackage[T1]{fontenc} \usepackage{amsmath} \usepackage{amsfonts} \usepackage{amssymb} \usepackage{csquotes} \usepackage{graphicx} \usepackage{pgfplots} \setbeamertemplate{theorems}[ams style] \begin{document} \begin{frame}{Theorems I} \begin{theorem} Suppose $|I|\geq3$ and $\Theta$ is \textbf{rich}:\\ For any $i,~\theta'_i,~\theta_i$, manipulation $\theta'_i$ is an \textbf{OM} for $\theta_i$ under mechanism $\phi\iff$ for any mechanism $\psi$ \textbf{i-undistinguishable} from $\phi,~\theta'_i$ is a \textbf{profitable} manipulation for $\theta_i$ \end{theorem} \end{frame} \begin{frame}{Theorems II} \begin{figure} \centering \scalebox{.75}{\input{Plot1.tex}} %see my previous question %\caption{} %\label{fig:f1} \end{figure} \end{frame} \begin{frame}{Theorem III} \begin{theorem} Any stable-dominating mechanism is \textbf{not obviously manipulable} \end{theorem} \pause \begin{theorem} Any stable mechanism is individually rational, Pareto efficient, and \textbf{not obviously manipulable} \end{theorem} \pause \begin{theorem} The $(K+1)$-price auction is \textbf{not obviously manipulable} \end{theorem} \pause \begin{theorem} Every efficient, individually rational, and weakly budget balanced mechanism is \textbf{obviously manipulable} \end{theorem} \end{frame} \end{document}
Improve this answer
1
  • 1
    Thanks for the user guide info, I must have missed that! The reason I wanted to use allowframebreaks or something similar was to have the automatic increment in the frame title. But I guess splitting the frames (as I had it originally) is my only option and I'll have to increment the frame title manually... Commented Jan 8, 2020 at 10:31

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.