First: I've split up my question(s) from Cleaning up code and here is one of the bullets, with the code somewhat reduced.
Consider
\DocumentMetadata{} \documentclass[ a4paper, 12pt ]{article} \usepackage[ math-style = TeX ]{unicode-math} \usepackage[ hmargin = 2.4cm, vmargin = 3cm ]{geometry} \usepackage{multirow} \usepackage{pst-eucl} \psset{ dimen = m, PointSymbol = none, PointName = none, MarkAngleRadius = 0.25, RightAngleSize = 0.2, LabelSep = -0.3 } \def\mlr{1} \newcommand*\saenk[1]{\raisebox{\fpeval{-5/9*\mlr}ex}{#1}} \newcommand*\nyLinje[2][c]{\begin{tabular}[#1]{@{}l@{}}#2\end{tabular}} \begin{document} \begin{center} \begin{tabular}{ |p{4.95cm}| >{\centering\arraybackslash}p{4.95cm}| >{\centering\arraybackslash}p{4.95cm}| } \hline \multicolumn{1}{|c|}{\multirow{2}{*}{\raisebox{\fpeval{-1.2*\mlr}ex}{Du kender \dots}}} & \multicolumn{2}{ c|}{\saenk{Du kan beregne \dots}} \\[\mlr ex] \cline{2-3} & \saenk{sider} & \saenk{vinkler} \\[\mlr ex] \hline Siderne~$a$ og~$b$\hspace*{2em}% \raisebox{\fpeval{-4.5*\mlr}ex}{% \begin{pspicture}(0,-0.38)(1.33,1.5) \small \pstGeonode(0,0){A}(1,1.5){B}(1,0){C} \pspolygon(A)(B)(C) \pstRightAngle{B}{C}{A} \uput{0.1}[315](C){$C$} {\psset{ linestyle = none } \pcline[offset = 6pt](B)(C) \ncput{$a$} \pcline[offset = 7pt](C)(A) \ncput{$b$}} \end{pspicture}} & $c = \sqrt{a^{2} + b^{2}}$ & \parbox{4cm}{\vspace*{-1ex}\begin{align*} A &= \tan^{-1}{\mkern -7mu}\left(\frac{a}{b}\right){\mkern -7mu}\\ B &= \tan^{-1}{\mkern -7mu}\left(\frac{b}{a}\right){\mkern -7mu} % \\ &= \ang{90} - A \end{align*}\vspace*{-1ex}} \\[\mlr ex] \hline Siderne~$a$ og~$c$\hspace*{2.06em}% \raisebox{\fpeval{-4.5*\mlr}ex}{% \begin{pspicture}(0,-0.35)(1.33,1.5) \small \pstGeonode(0,0){A}(1,1.5){B}(1,0){C} \pspolygon(A)(B)(C) \pstRightAngle{B}{C}{A} \uput{0.1}[315](C){$C$} {\psset{ linestyle = none } \pcline[offset = 6pt](B)(C) \ncput{$a$} \pcline[offset = 6pt](A)(B) \ncput{$c$}} \end{pspicture}} & $b = \sqrt{c^{2} - a^{2}}$ & \parbox{4cm}{\begin{align*} A &= \sin^{-1}{\mkern -7mu}\left(\frac{a}{c}\right){\mkern -7mu}\\ B &= \cos^{-1}{\mkern -7mu}\left(\frac{a}{c}\right){\mkern -7mu} \end{align*}} \\[\mlr ex] \hline \end{tabular} \end{center} \end{document} Question
How do I make all the table cells (except the header) have the same height?

\vrule width 0pt height 6cm depth 1cm\relax(clearly hidden with a macro...):-)