A man page for fork, for example, is in the System Calls section that has number 2:
man 2 fork
How do you see what else is section 2 without resorting to Google?
A man page for fork, for example, is in the System Calls section that has number 2:
man 2 fork
How do you see what else is section 2 without resorting to Google?
To list all installed man pages from a specific section you can use apropos:
apropos -s 2 . # use an regex for apropos . means anything apropos -s 2 -w '*' # use unix globbing for apropos man -a -s 2 '*' Manpages are usually placed in /usr/share/man, but check $MANPATH, and are organized into sections like so:
Section 1: /usr/share/man/man1/ Section 2: /usr/share/man/man2/ ... So to list all installed section 2 manpages, do:
ls /usr/share/man/man2/ Or the more complete one:
find $(echo $MANPATH | tr ':' ' ') -path '*/man2/*' The latter one will have problems if you have directories in $MANPATH with space in their names.
On most distributions you can also check available man pages with a package tool, e.g. on Debian derived distributions you can use apt-file like so:
apt-file search /man2/ lman 2 and lists the unadorned name for each page on a new line and pages them. The function's body is: find $(man --path | tr ':' ' ') -path "*/man$1/*"| xargs basename | sort | sed -E "s/\.$1(.gz)?\$//" | less This command lists the sorted names of all the entries in the given section:
man -aWS 1 \* | xargs basename | sed 's/\.[^.]*$//' | sort -u If you want to see the pathnames, use:
man -aWS 1 \* | sed 's/\.[^.]*$//' | sort This tells man to search a section for all commands using the wildcard pattern * (backslash-quoted so the shell doesn't interpret it). -a finds all matches, -W prints the pathnames instead of displaying the pages, and -S 1 specifies section one. Change the 1 to whatever section you want to search.
The sed command strips the filename extensions; remove it if you want to see the complete filenames. sort sorts the results (-u removes duplicates).
For convenient reuse, this defines a Bash shell function:
function mansect { man -aWS ${1?man section not provided} \* | xargs basename | sed 's/\.[^.]*$//' | sort -u; } For example, you can invoke it as mansect 3 to see the entries in section three.
[Tested on macOS.]
uniq in the pipeline doesn't fix. sort -u to remove duplicates. No manual entry for * On Mac OS X, the only thing I can get to work is man -k . | grep -F '(3)', which lists everything in section 3.
I know this is a very old question, however the answers given here all didn't work for me. Therefore I came up with the following one-liner that works on Ubuntu 18.04 and macOS Mojave, 10.14.6:
find $(man --path | tr ':' ' ') -type f -path '*man2*' \ -exec basename {} \; | sed 's/\..*//' | sort Quick run down:
$(man --path | tr ':' ' ') to get the current paths of the man pages find <man paths> -type f -path '*man2*' -exec basename {} \; gets the file names of all regular files in the man pathssed gets rid of the file extensionsort alphabetically.man man for more details. (In particular, it can search for things 'near the roots', and all sectionN pages aren't under manN subfolders.)