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How to get count of files in a directory starting with specific text like dataxxx.csv

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    What is "a directory start"? Do you want to search in a directory named "start". Do you want to search for file with names starting with "dataxxx.csv" (e.g. dataxxx.csv.123.jpeg)? Or does the text have to in the file? At the start of the files you want to count? Please rewrite you question so it is less ambiguous. Commented Dec 14, 2014 at 8:12

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There are probably fancier ways, but what works for me is 

ls /directory/data* | wc -l
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  • foo=$(ls /directory/data* | wc -l) Commented Dec 14, 2014 at 7:49
  • Shouldn't that be data*.csv? And in your comment, there ought to be double-quotes around the $(). Of course, this strategy will not give a correct count if there are files that match the pattern which happen to have a newline char in their name. :) Commented Dec 14, 2014 at 12:48
  • Yes, of course it can be data*.csv as well :) I haven't quoted $() when I do this kind of thing and haven't noticed anything breaking. I assume something could - what? And you're of course right about about the names. In any case there are now better answers for the OP than mine :) Commented Dec 14, 2014 at 13:01
  • The naked $() is ok here, but it's a good habit to double quote stuff: From BashGuide As with all substitutions, the results of a command substitution will undergo WordSplitting, unless the whole thing is inside double quotes. So as a rule, quote stuff unless you explicitly want to invoke word splitting. Commented Dec 15, 2014 at 3:59
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Using find to test that they are a file (-type f) and match the required pattern ("data*.csv"):

find directory/ -type f -name "data*.csv" | wc -l
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  • jasonwryan, your code find the files in subdirectory also but how can i find files only in current directory? Commented Dec 14, 2014 at 8:26
  • @user188979 you would use find . -maxdepth 1 ... to restrict the search to just the current directory. Commented Dec 14, 2016 at 23:21

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