I'm trying to remove the content from the beginning of the text to the first blank line.
--($:~)-- cat example.txt pedro pablo juan francisco emiliano martin So, I would delete:
pedro pablo juan I tried with:
sed -n '/^/,/^$/ d' example.txt but it doesn't work.
You can do
sed -n '/^$/{:l; p; n; b l}' file The -n suppresses normal output. When you reach the first blank line, which is matched with the pattern /^$/, it starts a loop that prints all subsequent lines.
With sed:
sed -n '/^$/,$p' file or:
sed -e '/^$/,$!d' file With awk:
awk '/^$/{p++};p' file With a recent ksh (you need ksh93s or above), you could do:
cat <example.txt <#"" 
sed -e 1,/^$/c\\ -e '' <infile >outfile ...would also work.
As opposed to 1,/^$/d the c\<EOF> command doesn't delete the address range, exactly, but rather changes the whole block to a single string. And so this will not remove the first blank line from output - because it changes the whole first occurring text block in input (as delimited by the first occurring blank line) to a single blank line.
