How to escape an input string in Bash [closed]

Question

I'm using the jq tool to handle some JSON in bash.
Just one problem, while using this line:

PB_ACL="acl="`echo $IMGREQ | jq -r'.data.acl'`

Result:

echo $PB_ACL // acl=

The expected value jq has to filter out is: "acl":"public-read" But it's not working now. I think it has to to with the dash (-) symbol.

How do I escape such incoming string data?

Try PB_ACL="acl=$(echo $IMGREQ | jq -r'.data.acl')" (Or use the backticks, just leave it inside the double quotes) — user43791
– user43791, Commented Jul 2, 2015 at 20:38
The command between the backticks to be processed. (Command Substitution) So Im afraid this ain't gonna work... — Milkmannetje
– Milkmannetje, Commented Jul 2, 2015 at 20:40
I'm not sure I understand your comment but command substitution do occur inside double quotes. — user43791
– user43791, Commented Jul 2, 2015 at 20:41

Milkmannetje · Accepted Answer · 2015-07-02 20:50:18Z

2

Missed a space:

PB_ACL="acl="`echo $IMGREQ | jq -r '.data.acl'` ^

answered Jul 2, 2015 at 20:50

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