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I want to list the number of directories under each subdirectory tree of the present directory. As there are too many directories, I can't go into individual directories and check. I would like to produce a report something like the one shown in the following picture:

enter image description here

The issue is: my server is giving some warning that the maximum limit of creating directories is reached. So I wanted to know which directory in my parent directory has the maximum sub-directories (excluding files),

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  • A small change: where in the pic it says -dir1 -- 8000 (total count of only dirs including all sub directories,no files).. Commented Jul 17, 2015 at 13:01
  • possible duplicate of Where are my inodes going? Commented Jul 17, 2015 at 23:10
  • Are you concerned about reaching the inode limit, the path length, or something else? Commented Jul 17, 2015 at 23:49
  • All these answers, not even a single explanation of what is doing what. Magic is magic indeed. Commented Jul 18, 2015 at 1:51
  • I am getting an error in /var/adm/messages "vxfs: [ID 702911 kern.warning] WARNING: msgcnt 5555 mesg 128: V-2-128: number of links reached vx_maxlink for inode 53685 on filesystem". And on searching about it i found out that it is due to the number of sub-directories in FS reaching a limit 32k. Commented Jul 21, 2015 at 15:30

5 Answers 5

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Pure ksh93 solution:

FIGNORE='@(.|..)' for dir in */; do a=( "$dir"/**/* ); printf "%s\t%s\n" "$dir:" "${#a[*]}"; done

Result from /usr/src:

linux-3.17.7-gentoo/: 561 linux-3.5.7-gentoo/: 517 linux-3.7.10-gentoo/: 505 linux-3.7.9-gentoo/: 513 linux-3.8.13-gentoo/: 551 linux-4.0.5-gentoo/: 1849
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  • this commands seems to be giving total number of files + directories. can you modify it just to give directories(and all the sub-directories under it) Commented Jul 21, 2015 at 15:45
  • @MostWanted Just remove double dots glob: for dir in */; do a=( "$dir"/* ); printf "%s\t%s\n" "$dir:" "${#a[*]}"; done Commented Jul 21, 2015 at 17:56
  • This command didn't give me the right output. Might be it was not checking under all the levels of the sub-directories. I have explained the question with an example image. Can you please check and provide the new command. Commented Jul 29, 2015 at 21:57
  • @MostWanted Which shell are you using? This command gives me right answer on bash and zsh. I don't have ksh at hand to check. The glob **/* descent into all subdirectories recursively so will give you total number of files and directories. You may need to set some option to make ** work, as setopt -s globstar in bash. Commented Jul 29, 2015 at 23:12
  • my server uses bash.. Commented Jul 30, 2015 at 18:27
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You could find the toplevel directories first, then use a second find, to count the number of files and directories within the toplevel directory:

$ for dir in $(find . -maxdepth 1 ! -path . -type d | sort); \ do echo -n "$dir " && find $dir ! -path . | wc -l ; done ./adir 1151 ./anotherdir 140 ./623de41e44 280 ./examples 154 ...
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Will something like this suit your need:

The path /boot is used for sample demonstration. Change it to the directory you need.

for DIR in $(find /boot/* -maxdepth 1 -type d) do printf "%40s: %10d\n" "${DIR}" $(find ${DIR}|wc -l) done

Output:

 /boot/grub: 282 /boot/grub/fonts: 2 /boot/grub/i386-pc: 272 /boot/grub/locale: 4 /boot/lost+found: 1
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try

 find * -print | awk -F/ '{c[$1]++;} END { for (c2 in c) printf "-%s -- %d\n",c2,c[c2] ;} '

where

  • find from directory above the ones you want to sum up
  • awk will count top level dir and file and sum up at the end.
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The following little loop will list a count of all files (excepting symlinks) in child directories of . which exist on the same filesystem as the child directory.

for d in ./* ./.[!.]* ./..?* do ! [ -h "$d" ] && cd "$d" 2>&3 || continue printf "%s:\t" "$d" find .//. -xdev -depth ! -type l | grep -c '^\.//\.' cd .. done 3>/dev/null
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