How to grep an XML tag and get only the value inside the quotes after it?

Question

I'm trying to get these values from the XML format below: USA GERMANY

<country name="USA" id="TEST1" password="123" /> <country name="GERMANY" id="TEST2" password="456" />

I was checking xmllint but I don't have --xpath installed and I just can't quite get the exact combination to get those values using grep.

To reinforce the comment that grep is a bad choice: No matter what you do, it will totally fail as soon as the XML files get formatted bit differently, e.g. with line breaks. There are enough XML tools, or alternatives like sgrep available you don't need to rely on grep. — dirkt
– dirkt, Commented Mar 17, 2018 at 6:44

nxnev · Accepted Answer · 2018-03-15 04:19:21Z

0

This works for me:

grep -P -o -e '(?<=name=").*?(?=")'

answered Mar 15, 2018 at 4:12

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