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It has been awhile since I have had to drive into shell scripting. However, I have a shell script where I'm renaming files based on the file extension from a ftp upload.

Currently, the files are uploaded to the server via an FTP process. All files are renamed from filename.txt to filename.dat. What I would like to do is only rename the files based on the file's modified date after a certain number of minutes.

i.e. all files whose modified time is greater than five (5) minutes.
-mtime -5.

Below is my shell script: 

#!/bin/bash for name in /u/easy/ep2/data/download/*.txt; do newname=${name%.txt}.log mv "$name" "$newname" done
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You need +5 for more than 5 minutes.

find /u/easy/ep2/data/download -maxdepth 1 -name '*.txt' -mtime +5 \ -exec sh -c 'mv "$1" "${1%.txt}.log"' arg0ignored {} \;

Edit

Example:

$ find /tmp -maxdepth 1 -name '*.txt' -mtime +5 -exec sh -c 'echo mv "$1" "${1%.txt}.log"' x0 '{}' \; mv /tmp/1.txt /tmp/1.log mv /tmp/2.txt /tmp/2.log
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  • Sorry, I should have included the Linux version. We are running RedHat Enterprise v 7.4. Commented Aug 9, 2018 at 19:00
  • This is the error message I get when I run the script from the command line or inside the script. find: paths must precede expression: -exec Commented Aug 9, 2018 at 19:08
  • I have GNU find 4.6.0, for me this works. I forgot the arg0, that is ignored, but that shouldn't lead to this message. Commented Aug 9, 2018 at 19:17
  • I will give that a try! Thank you for your help! Commented Aug 9, 2018 at 19:18
  • Still returns the same error message when I added the arg0ignored. Commented Aug 9, 2018 at 19:23

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