Show line numbers of a file after "cut -d ";" -f3 |uniq -d"

With GNU sort and GNU uniq, you could do:

$ <FILE.txt awk -F';' '{print NR"- "$3}' | sort -st' ' -k2 | uniq -Df1 2- POLICE 4- POLICE 

Lines are sorted first lexically on the text and then by number (-s preserves the original order for texts that sort the same). Add a | sort -n to sort by line number.

With awk alone:

awk -F';' '!x {c[$3]++}; x && c[$3] > 1 {print FNR"- "$3}' FILE.txt x=1 FILE.txt 

It seems unlikely that your current pipeline works in the way you claim but it does not with BSD or GNU tools. Not sure if you are using something different.

I was able to come up with the following loop to to accomplish what you are asking:

for prof in $(cut -d\; -f3 FILE.txt | sort | uniq -d); do awk -v pat="$prof" -F\; '$3 ~ pat{print NR"-",$3}' FILE.txt done 

This will produce a list of professions that appear more than once and then use awk to find each occurance of them in the file, printing the line number and profession name.

awk will set the profession gathered from the cut -d\; -f3 FILE.txt | sort | uniq -d pipeline to the pat parameter and then search the file for lines containing that pattern in the 3rd field (using ; as a field separator). For lines that match it will print the line number and the 3rd field (separated by a dash).