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I have a shell script containing trap, but trap doesn't seems to work as expected below is the code and bash version

GNU bash, version 4.2.46(2)-release (x86_64-redhat-linux-gnu)

set -e function exit_message(){ echo -e "\e[31m\nError occurred " } function login(){ false } trap exit_message ERR login

Above trap works if I do

function login(){ trap exit_message ERR false }
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  • no discussion about set -e is complete without a link to this table ;-) Commented Jun 1, 2019 at 21:16

1 Answer 1

Reset to default
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From the bash manual:

All [...] aspects of the shell execution environment are identical between a function and its caller with these exceptions: the DEBUG and RETURN traps are not inherited unless the function has been given the trace attribute using the declare builtin or the -o functrace option has been enabled with the set builtin, (in which case all functions inherit the DEBUG and RETURN traps), and the ERR trap is not inherited unless the -o errtrace shell option has been enabled.

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  • I am still not clear what is workaround Commented Jun 1, 2019 at 16:33
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    set -o errtrace, as it says. Commented Jun 1, 2019 at 17:15

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