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i need help. i have this file i want read it line by line with for loops and delete the line less than 20% the number will with list %CPU .

%CPU PID USER UID COMMAND %MEM 71 9136 ashti 1000 firefox 4.6 36 1432 ashti 1000 gnome-shell 8.6 25 9100 ashti 1000 gedit 1.1 3 9092 ashti 1000 nautilus 1.2 2 9109 ashti 1000 gnome-terminal- 0.9 1 1248 ashti 1000 Xorg 2.6 0 1375 ashti 1000 VBoxClient 0.0 0 9118 ashti 1000 bash 0.1 0 269 root 0 systemd-journal 2.8

i want be like this example 

%CPU PID USER UID COMMAND %MEM 71 9136 ashti 1000 firefox 4.6 36 1432 ashti 1000 gnome-shell 8.6 25 9100 ashti 1000 gedit 1.1

and save in new file .

best regards

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  • why are you requiring the use of a for loop? Commented Oct 29, 2019 at 18:01
  • is this a school assignment? Commented Oct 29, 2019 at 18:02
  • please check this link its my code question [link] (unix.stackexchange.com/questions/549368/…) Commented Oct 29, 2019 at 20:01
  • If you are using Ubuntu you can post these questions in Ask Ubuntu What command did you use to generate the CPU%? It appears like it needs to be divided by the number of CPU cores for an accurate percentage. Commented Oct 30, 2019 at 0:09

3 Answers 3

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With grep:

grep -e "^%" -e "^[2-9][1-9]" file | column -t

column -t to make it pretty:

%CPU PID USER UID COMMAND %MEM 71 9136 ashti 1000 firefox 4.6 36 1432 ashti 1000 gnome-shell 8.6 25 9100 ashti 1000 gedit 1.1
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With retaining header, awk expression:

$ awk 'NR==1 || (NR > 1 && $1 > 20)' file %CPU PID USER UID COMMAND %MEM 71 9136 ashti 1000 firefox 4.6 36 1432 ashti 1000 gnome-shell 8.6 25 9100 ashti 1000 gedit 1.1
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A for loop is not a good choice for this task - for a discussion of the reasons why, see for example

My personal choice would be Miller:

$ mlr --pprint filter -x '${%CPU} < 20' file > newfile $ cat newfile %CPU PID USER UID COMMAND %MEM 71 9136 ashti 1000 firefox 4.6 36 1432 ashti 1000 gnome-shell 8.6 25 9100 ashti 1000 gedit 1.1
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