I have a list of usernames which i need to sync their passwords over to a new server.
How would I go about extracting the username and password hash from the /etc/security/passwd file into the below format
username:MGURSj.F056Dj The passwd file is in stanza format
username: password = MGURSj.F056Dj lastupdate = 623078865 You could parse the file with awk:
awk ' /^[[:alnum:]]*:/ { user=substr($0, 1, index($0, ":") - 1) } /^ *password *=/ { split($0, elements, " *= *"); print user ":" elements[2] }' \ /etc/security/passwd The idea behind the script is to first find the username line -- one starting with and containing alphanumeric characters, followed by a colon -- and extract that username with the "substr" function. On lines that start with zero or more spaces followed by the string "password", followed by zero or more spaces and an equals-sign, we split the line across the equals-sign and print the saved username with the password portion of the current line.
In case of an AIX system and the usernames are know, I would use another way like:
HASH=$(grep -p $USERNAME /etc/security/passwd | awk '/password/ {print $3}') echo "${USERNAME}:$HASH" Certainly the search for "password" could be coded even more strictly.
username:hash. $ missing between = and ( ?