How can I colorize directories contain files with word INCORRECT inside?
Example:
I have 3 directories which contain log file.
dir_a/log dir_b/log dir_c/log The file log in dir_c contain word INCORRECT Is it possible to get colorized ls output as following?
dir_a --> blue dir_b --> blue dir_c --> red This should do the job:
"INCORRECT" in text inside of files inside of folders and files within given folder:
SEARCH_DIR="/var/log" for i in $(find $SEARCH_DIR -maxdepth 1 -mindepth 1); do DIR_CHECK=$(grep INCORRECT $i) [[ "$DIR_CHECK" =~ "INCORRECT" ]] \ && echo -e "\e[00;31m$i\e[00m" \ || echo -e "\e[00;32m$i\e[00m" done "INCORRECT in text inside of files inside of folders in the given folder":
SEARCH_DIR="/var/log" for i in $(find $SEARCH_DIR -maxdepth 1 -mindepth 1 -type d); do DIR_CHECK=$(grep INCORRECT $i) [[ "$DIR_CHECK" =~ "INCORRECT" ]] \ && echo -e "\e[00;31m$i\e[00m" \ || echo -e "\e[00;32m$i\e[00m" done "INCORRECT" in name of folders and files in given folder:
SEARCH_DIR="/var/log" for i in $(find $SEARCH_DIR -maxdepth 1 -mindepth 1); do DIR_CHECK=$(echo $i | grep INCORRECT) [[ "$DIR_CHECK" =~ "INCORRECT" ]] \ && echo -e "\e[00;31m$i\e[00m" \ || echo -e "\e[00;32m$i\e[00m" done "INCORRECT" in name of folders in given folders:
SEARCH_DIR="/var/log" for i in $(find $SEARCH_DIR -maxdepth 1 -mindepth 1 -type d); do DIR_CHECK=$(echo $i | grep INCORRECT) [[ "$DIR_CHECK" =~ "INCORRECT" ]] \ && echo -e "\e[00;31m$i\e[00m" \ || echo -e "\e[00;32m$i\e[00m" done No, at least in the current implementations of ls. The maximum you can do is selecting colors depending on the file type (image, sound recording etc., based on file name mask), entry type (file, directory, socket etc.) and, partially, permissions (executable flags). You are not able to apply color for directory depending even on the files it contains, not saying about the content of those files.
lshad to read the file first, which slows down directory listing.