Assume the content:
foo fnord bar;" >> /tmp/foo/derp gnarf foo fnord bar;" >> /tmp/foo/derp I want to jump to the " and delete to end of line and repeat that over the rest of lines.
Yet when I:
f"d$ j . it only deletes from my current cursor position to the end of file.
foo fnord bar; gnarf foo fno Yet I would have expected the line to read:
gnarf foo fnord bar; How can I have vim repeat the jump movement as well on repeat?
From the repeat documentation :
. Repeat last change, with count replaced with [count]. Also repeat a yank command, when the 'y' flag is included in 'cpoptions'. Does not repeat a command-line command. So, as expected, you're repeating the last change (d$).
If you want to repeat your movement, use ;:
; Repeat latest f, t, F or T [count] times. See |cpo-;| IE:
f"d$ j ;. You could map a binding to perform ;. at the same time, if you want.
Like so:
:%s/".*$/ This will substitute everything from the quote to the end of the line with nothing, hence deleting it.
Note that '%' will apply the operation to the whole file.
Use a range instead of % to change a specific sequence of lines:
:1,17s/".*$/ to change lines 1 thru 17, or:
:.,+3s/".*$/ to change the current line and the following 3.
You should see the selections to be changed being highlighted as you type the regular expression, so you'll know if you got it right or not.
PS Yes, I know this is four years too late, but I'm doing this for my own education. The best way to learn is to teach :)
;. approach from the accepted answer. :.,$s/patter/replace To change from current line to end of file
qqf"d$j