Thread: how to do dynamic casting for all datatypes

ublic class MethodsExample {   public void add(int a, int b) { int add = a + b; System.out.println("Addtion value=" + add); }   public void sub(int a, int b) { int sub = a - b; System.out.println("Substraction value=" + sub); }   public void mul(int a, int b) { int mul = a * b; System.out.println("Multiplication value=" + mul); }   public void div(int a, int b) { int div = a / b; System.out.println("Division value=" + div); }   public static void main(String[] args) {	MethodsExample obj = new MethodsExample();	obj.add(5, 6);	obj.sub(5, 6);//here if i want any other data types to pass as a parameter what i ve to do for that please help me	obj.mul(5, 6);	obj.div(5, 6);  	obj.add(100, 500);	obj.add(800, 900);   }   }

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if i sent by different data types i ve to get convertes in that method 'm not getting how to do that please help me

no i want in main method if i send any other datatypes exbj(2.0,3.0) i want it convert in the method as generic if i want to put any type of data type parameters when i called t have to convert to that type for that what i have to do is there any method like type cast of generally or i have to use switch for every data types?????/ please help me

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9 if i want any of method called in different data types like obj.add('a','b') or obj.add(2.0,5.0) i want to convert in method parameters when i called in main method for that what i have to do generically please help me its urgent public static void main(String[] args) { MethodsExample obj = new MethodsExample(); obj.add(5, 6); obj.sub(5, 6);//here if i want any other data types to pass as a parameter what i ve to do for that please help me obj.mul(5, 6); obj.div(5, 6);

Are you talking about method overloading? Having multiple methods with the same name but different parameters?

Have you tried writing the code using generics? The code in post#1 does not use generics. Try rewriting the code to use generics.
For example:

 public class MethodsExample<T> {   ... MethodsExample<Double> me = new MethodsExample<Double>(); me.add(1.2, 2.3); // and MethodsExample<Integer> me2 = new MethodsExample<Integer>(); me2.add(12, 23);

Continuing on Norm's suggestion and going along with your current question, consider restricting your generic arguments to numeric values only (if that is what you want).

For example (stealing Norm's code):

 public class MethodsExample<T extends java.lang.Number> {   ... MethodsExample<Double> me = new MethodsExample<Double>(); me.add(1.2, 2.3); // and MethodsExample<Integer> me2 = new MethodsExample<Integer>(); me2.add(12, 23);

To call the methods with the same names but different data types for its args,
either define overloaded methods each with the desired data type
or use generics and define a class to handle the desired data type

Actually, this is far more complex than I assumed because you cannot do arithmetic on a Number object...
Hmm... There is certainly a messy way of doing this, but I do not know if there is a generic way of doing this.
The messy way of doing it would be something like:

public <T extends Number> T add(T val1, T val2) { if(val1 instanceof Integer) { return (T)new Integer((Integer)val1 + (Integer)val2); } else if(val1 instanceof Double) { return (T)new Double((Double)val1 + (Double)val2); } // And follow this pattern for every Number type }

It is not ideal. Maybe someone else has a better idea.