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I have this from the matlab reference manual

value = getfield(struct, 'field')

where struct is a 1-by-1 structure, returns the contents of the specified field, equivalent to

value = struct.field

how can I do the opposite

getStringName(struct.field) which return 'field'

also if it is possible to point at the field in numerical way similar to an array

like struct{1} for field 1 field

edit

if I do the follow

structName(1) I get a list of field names, and dimentions

 Speed: [2244x1 double] Time: [2244x1 double] ... and so on

I want to grab the title speed as string, and if possible

structName(1).filed(1) for Speed without doing structName(1).Speed

I want to print each field into a file with the field name!

so if I do

for i=1:sizeOfStruct printToFile(structName(i)); %<=== accessing field by index, problem 2 end function printToFile(structField) structFieldStr = getStrFiledName(structField); %<=== obtain field string, main problem filename = strcat(fileLoc, '/profile/', structFieldStr, '.dat'); %... then open file and dump everything end
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  • Unless it appears left of an assignment, struct.field is just a value, for example 2.5, and no longer has any ties to the struct object. Commented Sep 24, 2013 at 19:09
  • Does the fieldnames function give what you want, or are you trying to find the field which contains a certain value? You can also try inputname, not sure if that works with structure members Commented Sep 24, 2013 at 19:26
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    fieldnames gave me one part, whats left is grabbing that field by its location, or field name Commented Sep 24, 2013 at 19:34

1 Answer 1

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Not the complete answer to your question, but this should get you started:

s.a = 11; s.b = 22; s.c = 33; names = fieldnames(s); for i = 1:length(names) fprintf('Field %s = %g\n', names{i}, s.(names{i})) end

Result:

Field a = 11 Field b = 22 Field c = 33

Note the syntax to programmatically access a field name: s.(name), where s is a struct and name is a string.

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2 Comments

Reference to non-existent field 'fieldnames'. is the error I get if I tried s.fieldnames, however I used fieldnames(s), however s.(name) still not working 'Undefined function or variable 'a'.'
Sorry, I was still editing out some bugs, should work now. That is what you get when posting untested code ...

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