Run python code for 5 seconds then end [duplicate]

Question

The below is an extract from my code from a previous question. The aim of this python code is to create a crawler for Twitter where by I plan to run the code every hour for 60 seconds. I am going to do this over 24 hours for 7 days to look at the trends within Tweets.

Currently this code is running until it is manually ended

import time import threading class listener(StreamListener): def on_data(self, data): try: print data saveFile = open('twitDB.csv','a') saveFile.write(data) saveFile.write('\n') saveFile.close() return True except BaseException, e: print 'failed ondata,' ,str(e) time.sleep(5) def on_error(self, status): print status time.sleep(5)

So what is the problem, disregarding the contents of the listener class, what you have would do what you want if you repalces the time.sleep(60) with time.sleep(5) — user1888249
– user1888249, Commented Dec 26, 2013 at 15:43
You say “extract” from the code of the previous question when it’s actually mostly unchanged. The question does not seem any different at all—and actually there isn’t a question in what you have written. The previous question gives you enough ideas to work with, so please use those answers to solve it. — poke
– poke, Commented Dec 26, 2013 at 16:14
@poke, you are saying right.I just checked that the guy has asked almost the same question again. — darxtrix
– darxtrix, Commented Dec 26, 2013 at 16:50

darxtrix · Accepted Answer · 2013-12-26 16:09:16Z

Put the following code in a running thread other than in which your main code is executing and have a try:

import sys,time now=time.time() while True: end=time.time() total=round(end-now) if total==5: sys.exit(0)

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