Opening IDLE from another Python script with command line paramteters

Question

I am looking to open a Python script in edit mode in IDLE by passing in a directory from another Python script. I understand that I can use os.system to execute idle.py but I then don't know how to pass the appropriate -e parameter and get it to use a specific directory i.e. open something.py in diredtory C:\Python all from the original Python script.

Thanks for your help,

Ben

jayelm · Accepted Answer · 2014-02-12 18:38:09Z

2

You can use subprocess.call(). By setting shell = True, the function treats the string as a literal shell command. Modify the paths as you see fit.

import subprocess subprocess.call(r'C:\Python27\Lib\idlelib\idle.py -e C:\Python27\something.py', shell=True)

edited Feb 12, 2014 at 18:38

answered Jan 24, 2014 at 3:11

jayelm

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6 Comments

Ben Over a year ago

Should the not use forward slashes? For other operations, like os.chdir, an error is returned if forward slashes are not used, even on a Windows box.

Ben Over a year ago

I am afraid I think the rest of my program is so broken other errors are coming up before it even gets to this code. This is part of my first attempt at OOP programming so...

jayelm Over a year ago

@fluffybonkers Well, if it does return a syntax error, flip the slashes.

Ben Over a year ago

Just tested in isolation. It works but it opens up multiple IDLE windows.

jayelm Over a year ago

@fluffybonkers Try it without the -e?

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