I have a number like 601511616 If all number's length is multiple of 3, how can a split the number into an array without making a string
Also, how can I count numbers in the int without making a string?
Edit: Is there a way to simply split the number, knowing it's always in a multiple of 3... good output should look like this: {616,511,601}
You can use i % 10 in order to get the last digit of integer.
Then, you can use division by 10 for removing the last digit.
1234567 % 10 = 7 1234567 / 10 = 123456 Here is the code sample:
int value = 601511616; List<int> digits = new List<int>(); while (value > 0) { digits.Add(value % 10); value /= 10; } // digits is [6,1,6,1,1,5,1,0,6] now digits.Reverse(); // Values has been inserted from least significant to the most // digits is [6,0,1,5,1,1,6,1,6] now Console.WriteLine("Count of digits: {0}", digits.Count); // Outputs "9" for (int i = 0; i < digits.Count; i++) // Outputs "601,511,616" { Console.Write("{0}", digits[i]); if (i > 0 && i % 3 == 0) Console.Write(","); // Insert comma after every 3 digits } IDEOne working demonstration of List and division approach.
Actually, if you don't need to split it up but only need to output in 3-digit groups, then there is a very convenient and proper way to do this with formatting.
It will work as well :)
int value = 601511616; Console.WriteLine("{0:N0}", value); // 601,511,616 Console.WriteLine("{0:N2}", value); // 601,511,616.00 
I can't understand your question regarding how to split a number into an array without making a string - sorry. But I can understand the question about getting the count of numbers in an int.
Here's your answer to that question.
Math.Floor(Math.Log10(601511616) + 1) = 9 Edit: Here's the answer to your first question..
var n = 601511616; var nArray = new int[3]; for (int i = 0, numMod = n; i < 3; numMod /= 1000, i++) nArray[i] = numMod%1000; Please keep in mind there's no safety in this operation.
Edit#3
Still not perfect, but a better example.
var n = 601511616; var nLength = (int)Math.Floor(Math.Log10(n) + 1)/ 3; var nArray = new int[nLength]; for (int i = 0, numMod = n; i < nLength; numMod /= 1000, i++) nArray[i] = numMod%1000; Edit#3:
IDEOne example http://ideone.com/SSz3Ni
the output is exactly as the edit approved by the poster suggested.
{ 616, 511, 601 } 
Using Log10 to calculate the number of digits is easy, but it involves floating-point operations which is very slow and sometimes incorrect due to rounding errors. You can use this way without calculating the value size first. It doesn't care if the number of digits is a multiple of 3 or not.
int value = 601511616; List<int> list = new List<int>(); while (value > 0) // main part to split the number { int t = value % 1000; value /= 1000; list.Add(t); } // Convert back to an array only if it's necessary, otherwise use List<T> directly int[] splitted = list.ToArray(); This will store the splitted numbers in reverse order, i.e. 601511616 will become {616, 511, 601}. If you want the numbers in original order, simply iterate the array backwards. Alternatively use Array.Reverse or a Stack
Since you already know they are in multiples of 3, you can just use the extracting each digit method but use 1000 instead of 10. Here is the example
a = 601511616 b = [] while(a): b.append(a%1000) a = a//1000 print(b) #[616, 511, 601] 