Given a string, how do I truncate all characters following one particular character?
For example I have a url:
http://pics.v6.top.rbk.ru/v6_top_pics/resized/250xH/media/img/7/92/754435534528927.jpg"><div>Some text</div>" I want to strip all characters after the ", including the " character.
extension String { mutating func stripFromCharacter(char:String) { let c = self.characters if let ix = c.indexOf("\"") { self = String(c.prefixUpTo(ix)) } } } And here's how to use it:
var s = "http://pics.v6.top.rbk.ru/v6_top_pics/resized/250xH/media/img/7/92/754435534528927.jpg\"><div>Some text</div>" s.stripFromCharacter("\"") Probably the dumbest way to do it but it works.
let a = "http://pics.v6.top.rbk.ru/v6_top_pics/resized/250xH/media/img/7/92/754435534528927.jpg\"" + "><div>Some text</div>" print(a) var new = "" for char in a.characters{ if char == "\""{ break } new.append(char) } print(new) Maybe you simply want to use NSDataDetectors?
E.G. something like:
let input = "http://pics.v6.top.rbk.ru/v6_top_pics/resized/250xH/media/img/7/92/754435534528927.jpg"><div>Some text</div>"" let detector = try! NSDataDetector(types: NSTextCheckingType.Link.rawValue) let matches = detector.matchesInString(input, options: [], range: NSMakeRange(0, input.characters.count)) for match in matches { let url = (input as NSString).substringWithRange(match.range) print(url) } More info can be found in this HackingWithSwift blog post.
