why does my output is wrong in exponents in java [duplicate]

Question

why is it that this is wrong? i input the heightL as 2 the output must be 4 but there is something wrong

class He{ public static void main(String[] args) { int heightL=2; int a = 9; System.out.println(Math.abs(a)); System.out.println(2^(heightL)); } }

why is it that the output in the second part is 0?

A fast way to do 2 to the power of is either 1L << x for a long or Math.scaleb(1, x) for a double. — Peter Lawrey
– Peter Lawrey, Commented Nov 30, 2015 at 7:44

Eran · Accepted Answer · 2015-11-30 07:08:02Z

4

^ is not an exponent operator, it's bit-wise XOR (and 2 XOR 2 is 0).

For exponent, use Math.pow(2,heightL).

answered Nov 30, 2015 at 7:08

395k57 gold badges726 silver badges793 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

sir why is it possible loss of precision.?

@Hello23 Where do you see possible loss of precision?

thank you sir its already working..