How could I get all subfolders of some folder? I would use JDK 8 and nio.
for example, for folder "Designs.ipj" method should return {"Workspace", "Library1"}
Thank you in advance!
4
- 2You should edit your post and include the image in your question. Eventually external links become unavailable at some point and as such preventing future users to benefit from your question.Andrej– Andrej2016-07-08 14:26:36 +00:00Commented Jul 8, 2016 at 14:26
- docs.oracle.com/javase/tutorial/essential/io/dirs.html#listdirFildor– Fildor2016-07-08 14:28:14 +00:00Commented Jul 8, 2016 at 14:28
- hmmm do you need non-blocking IO for this ?niceman– niceman2016-07-08 14:29:30 +00:00Commented Jul 8, 2016 at 14:29
- I couldn't add picture because my rating is too low.M. Black– M. Black2016-07-08 14:44:04 +00:00Commented Jul 8, 2016 at 14:44
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2 Answers
List<Path> subfolder = Files.walk(folderPath, 1) .filter(Files::isDirectory) .collect(Collectors.toList()); it will contains folderPath and all subfolders in depth 1. If you need only subfolders, just add:
subfolders.remove(0); 
1 Comment
lisyara
DirectoryStream<Path> paths = Files.newDirectoryStream(folder, entry -> Files.isDirectory(entry)); much shorter
You have to read all the items in a folder and filter out the directories, repeating this process as many times as needed.
To do this you could use listFiles()
File folder = new File("your/path"); Stack<File> stack = new Stack<File>(); Stack<File> folders = new Stack<File>(); stack.push(folder); while(!stack.isEmpty()) { File child = stack.pop(); File[] listFiles = child.listFiles(); folders.push(child); for(File file : listFiles) { if(file.isDirectory()) { stack.push(file); } } } see Getting the filenames of all files in a folder A simple recursive function would also work, just make sure to be wary of infinite loops.
However I am a bit more partial to DirectoryStream. It allows you to create a filter so that you only add the items that fit your specifications.
DirectoryStream.Filter<Path> visibleFilter = new DirectoryStream.Filter<Path>() { @Override public boolean accept(Path file) { try { return Files.isDirectory(file)); } catch(IOException e) { e.printStackTrace(); } return false; } try(DirectoryStream<Path> stream = Files.newDirectoryStream(directory.toPath(), visibleFilter)) { for(Path file : stream) { folders.push(child); } } 
