How to check if a three digit number is a palindrome? [duplicate]

Question

I am creating a little trivial palindrome quiz in Java.

I should at some point check if the user will enter more or less than a three digit number such as "1011" or "10" and display an error message such as "Wrong input." However, I can't check the length of a number with int.length() in Java, as I instead could do with a String (String.length()).

How could I solve this problem?

This is my code without the if-three-digit check

import java.util.Scanner; public class Test { public static void main(String[] args) { System.out.println("Please enter a three digit number number and I will check if it's a palindrome."); // create scanner and input number Scanner input = new Scanner(System.in); int number = input.nextInt(); int digit1 = (int)(number / 100); int remaining = number % 100; int digit3 = (int)(remaining % 10); System.out.println(number + ((digit1 == digit3) ? " is a palindrome" : " is not a palindrome")); } }

check if number < 1000 && number >= 100. :| besides, you're doing numberAsString. you could call length() on this to get the length of the string. — Mridul Kashyap
– Mridul Kashyap, Commented Aug 8, 2016 at 7:54
if the number is int you can use this: number < 1000 && number >= 100. but i'd advise against it for a palindrome. why? what if the user enters 010. for int, it'll be seen as 10 and hence give an error. but as string, it'll be a palidrome. it's up to you to decide which result you wanna show to user, and hence use that method. — Mridul Kashyap
– Mridul Kashyap, Commented Aug 8, 2016 at 8:10

Toxaris · Accepted Answer · 2016-08-08 08:03:42Z

To check whether a number has certain properties, it is best to use numeric operations, if possible. This usually leads to faster and more straight-forward code.

The smallest number with three digits is 100. The largest number with three digits is 999. So you can test as follows:

if ((number < 100) && (number > 999)) { System.out.println("Not a three-digit number :(") }

SCouto · Accepted Answer · 2016-08-08 07:55:41Z

1

You can turn your int to String and use the length function.

Integer.toString(yourNumber).length()

answered Aug 8, 2016 at 7:55

SCouto

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2 Comments

RealSkeptic Over a year ago

This is a very roundabout and inefficient way when you can just check if the number is greater than 100 and less than 1000, two comparisons, no (hidden) loops.

m.rossi Over a year ago

I feel very stupid now that I understand I was struggling to write the inefficient and wrong solution to the problem. Thank you all, I knew there was a better way to do this but I didn't noticed.

pzaenger · Accepted Answer · 2016-08-08 08:42:08Z

Add an if condition once you get the input:

if (number >= 100 && number < 1000) { //Proceed with your logic } else { //Throw you message as invalid number }

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